Linux 找到匹配的文本并替换下一行
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find matching text and replace next line
提问by bswinnerton
I'm trying to find a line in a file and replace the next line with a specific value. I tried sed, but it seems to not like the \n. How else can this be done?
我正在尝试在文件中查找一行并用特定值替换下一行。我试过 sed，但它似乎不喜欢 \n。这还能怎么做？
The file looks like this:
该文件如下所示：
<key>ConnectionString</key>
<string>anything_could_be_here</string>
And I'd like to change it to this
我想把它改成这个
<key>ConnectionString</key>
<string>changed_value</string>
Here's what I tried:
这是我尝试过的：
sed -i '' "s/<key>ConnectionString<\/key>\n<string><\/string>/<key>ConnectionString<\/key>\n<string>replaced_text<\/string>/g" /path/to/file
采纳答案by potong
This might work for you (GNU sed):
这可能对你有用（GNU sed）：
sed '/<key>ConnectionString<\/key>/!b;n;c<string>changed_value</string>' file
!bnegates the previous address (regexp) and breaks out of any processing, ending the sed commands, nprints the current line and then reads the next into the pattern space, cchanges the current line to the string following the command.
!b否定前一个地址 (regexp) 并中断任何处理，结束 sed 命令，n打印当前行，然后将下一行读入模式空间，c将当前行更改为命令后面的字符串。
回答by Guru
One way: Sample file
一种方法：示例文件
$ cat file
Cygwin
Unix
Linux
Solaris
AIX
Using sed, replacing the next line after the pattern 'Unix' with 'hi':
使用 sed，将模式 'Unix' 后的下一行替换为 'hi'：
$ sed '/Unix/{n;s/.*/hi/}' file
Cygwin
Unix
hi
Solaris
AIX
For your specific question:
对于您的具体问题：
$ sed '/<key>ConnectionString<\/key>/{n;s/<string>.*<\/string>/<string>NEW STRING<\/string>/}' your_file
<key>ConnectionString</key>
<string>NEW STRING</string>
回答by Rubén Colomina
It works. Additionaly is interested to mention that if you write,
有用。另外有兴趣提到，如果你写，
sed '/<key>ConnectionString<\/key>/!b;n;n;c<string>changed_value</string>' file
Note the two n's, it replaces after two lines and so forth.
注意两个 n，它在两行之后替换，依此类推。
