仅获取路径目录并在 Java 中丢弃文件
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Get path directory only and discard file in Java
提问by kkk
How do we actually discard last file from java string and just get the file path directory?
我们如何实际丢弃 java 字符串中的最后一个文件并只获取文件路径目录？
Random Path input by user:
用户输入的随机路径：
C:/my folder/tree/apple.exe
Desired output:
期望的输出：
C:/my folder/tree/
closest solution i found is from here. The answer from this forum only display last string acquired not the rest of it. I want to display the rest of the string.
我找到的最接近的解决方案来自这里。该论坛的答案仅显示获得的最后一个字符串，而不显示其余的字符串。我想显示字符串的其余部分。
采纳答案by mvreijn
The easiest and most failsafe (read: cross-platform) solution is to create a Fileobject from the path.
最简单和最安全的（阅读：跨平台）解决方案是File从路径创建一个对象。
Like this:
像这样：
File myFile = new File( "C:/my folder/tree/apple.exe" );
// Now get the path
String myDir = myFile.getParent();
回答by Florent Bayle
Try that:
试试看：
String path = "C:/my folder/tree/apple.exe";
path = path.substring(0, path.lastIndexOf("/")+1);
