Python 如何从多维数组中返回最高值？
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How to return the highest value from a multi dimensional array?
提问by Abe Miessler
Say I have a multi dimensional array like the following:
假设我有一个多维数组，如下所示：
[
[.1, .2, .9],
[.3, .4, .5],
[.2, .4, .8]
]
What would be the best* way to return a single dimension array that contains the highest value from each sub-array ([.9,.5,.8])? I assume I could do it manually doing something like below:
返回包含每个子数组 ( [.9,.5,.8]) 中最高值的一维数组的最佳方法是什么？我假设我可以手动执行以下操作：
newArray = []
for subarray in array:
maxItem = 0
for item in subarray:
if item > maxItem:
maxItem = item
newArray.append(maxItem)
But I'm curious if there is a cleaner way to do this?
但我很好奇是否有更清洁的方法来做到这一点？
*In this case best = fewest lines of code
*在这种情况下最好=最少的代码行
采纳答案by wim
Since you mentioned in a comment that you are using numpy ...
由于您在评论中提到您正在使用 numpy ...
>>> import numpy as np
>>> a = np.random.rand(3,3)
>>> a
array([[ 0.43852835, 0.07928864, 0.33829191],
[ 0.60776121, 0.02688291, 0.67274362],
[ 0.2188034 , 0.58202254, 0.44704166]])
>>> a.max(axis=1)
array([ 0.43852835, 0.67274362, 0.58202254])
edit:the documentation is here
编辑：文档在这里
回答by squiguy
Using a list comprehension:
使用列表理解：
maxed = [max(sub_array) for sub_array in array]
回答by Dogbert
mapwith maxis cleaner IMO.
map与max更清洁的 IMO。
>>> arr = [
... [.1, .2, .9],
... [.3, .4, .5],
... [.2, .4, .8]
... ]
>>> map(max, arr)
[0.9, 0.5, 0.8]
地图文档。
回答by Joran Beasley
map(max,my_array)
I think thats pretty short ...
我认为那很短...
回答by Evgenii
Try this:
尝试这个：
max(array.flatten())
回答by user3503711
You can use numpy
你可以使用 numpy
import numpy as np
w = [[2,3,4],[5,6,7],[1,2,11]]
h=[]
for i in w:
h.append(np.amax(i))
print(h)
