php 从 JQuery 读取“echo json_encode()”的正确方法
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Correct way to read 'echo json_encode( )' from JQuery
提问by SirBT
I am using: echo json_encode($Response); to send an Associative array back to JQuery Ajax. Whenever I try to read each ID key value I get an undefined value. Please help me figure out what I am doing so wrong... Thanks in advance
我正在使用：echo json_encode($Response); 将关联数组发送回 JQuery Ajax。每当我尝试读取每个 ID 键值时，我都会得到一个未定义的值。请帮我弄清楚我做错了什么......提前致谢
My PHP Code:
我的 PHP 代码：
$Stuff = 'Hello world';
$Success = true;
$Content = $Stuff;
$Response = array('Success' => $Success, 'Content' => $Content);
echo json_encode($Response);
My JS code:
我的JS代码：
var sFirstName = $('#student_first_name').attr('value');
$.ajax({
type: "GET",
url: "../pgs/UpdateEditAStudent.php",
data: "FirstName="+ sFirstName ,
//The below code will give me: {"Success":true,"Content":"Hello world"}
success: function(data){$("#Ajax_response").html(data);}
//The popup window will show me "Undefined"
//and: {"Success":true,"Content":"Hello world"}
success: function(data){$("#Ajax_response").html(data); alert(data.Content);}
});
回答by Lumbendil
You should set the mime type aswell, wich, according to this questionis application/json. Then jQuery will understand the answer is a json element. To do it, you'd do the following:
您还应该设置 mime 类型，根据这个问题是application/json. 然后jQuery就会明白答案是一个json元素。为此，您需要执行以下操作：
header('Content-Type: application/json');
In your UpdateEditAStudent.phpbefore printing anything.
在您UpdateEditAStudent.php打印任何东西之前。
回答by Anthony Simmon
You don't have to add a header to the PHP file, just use this Jquery parseJSON function:
您不必向 PHP 文件添加标题，只需使用此Jquery parseJSON 函数：
Keep this PHP code as it is:
保持这个 PHP 代码不变：
$Stuff = 'Hello world';
$Success = true;
$Content = $Stuff;
$Response = array('Success' => $Success, 'Content' => $Content);
echo json_encode($Response);
And for the JS:
对于 JS：
$.ajax({
type: "GET",
url: "../pgs/UpdateEditAStudent.php",
data: "FirstName="+ $('#student_first_name').val(),
success: function(data){
// Here is the tip
var data = $.parseJSON(data);
alert(data.Content);
}
});
回答by Niklas
You need to define the correct dataTypeor provide the correct header, as Lumbendil described.
您需要定义正确的dataType或提供正确的标题，如 Lumbendil 所述。
You can manually define the dataTypeto json, so your code would look like:
您可以手动定义dataTypeto json，因此您的代码如下所示：
$.ajax({
type: "GET",
url: "../pgs/UpdateEditAStudent.php",
data: "FirstName="+ sFirstName ,
dataType: "json",
...etc
回答by Stefan H Singer
It's an array. You should probably do alert(data['Content']);.
这是一个数组。你可能应该做 alert(data['Content']);。
回答by asdasd
do something like this
做这样的事情
$Stuff = 'Hello world';
$Success = true;
$Content = $Stuff;
$Response = array('Success' => $Success, 'Content' => $Content);
echo json_encode($Response);
