从 JavaScript 数组中获取随机项

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时间:2020-08-23 19:30:14  来源:igfitidea点击:

Get random item from JavaScript array

javascriptarraysrandom

提问by James

var items = Array(523,3452,334,31,...5346);

How do I get random item from items?

我如何从 中获得随机物品items

回答by Kelly

var item = items[Math.floor(Math.random() * items.length)];

回答by Alnitak

If you really mustuse jQuery to solve this problem (NB: you shouldn't):

如果你真的必须使用 jQuery 来解决这个问题(注意:你不应该):

(function($) {
    $.rand = function(arg) {
        if ($.isArray(arg)) {
            return arg[$.rand(arg.length)];
        } else if (typeof arg === "number") {
            return Math.floor(Math.random() * arg);
        } else {
            return 4;  // chosen by fair dice roll
        }
    };
})(jQuery);

var items = [523, 3452, 334, 31, ..., 5346];
var item = jQuery.rand(items);

This plugin will return a random element if given an array, or a value from [0 .. n) given a number, or given anything else, a guaranteed random value!

如果给定一个数组,或者给定一个数字,或者给定其他任何东西,一个来自 [0 .. n) 的值,这个插件将返回一个随机元素,一个有保证的随机值!

For extra fun, the array return is generated by calling the function recursively based on the array's length :)

为了更有趣,通过基于数组的长度递归调用函数来生成数组返回:)

Working demo at http://jsfiddle.net/2eyQX/

http://jsfiddle.net/2eyQX/ 上的工作演示

回答by chim

Use underscore (or loDash :)):

使用下划线(或 loDash :)):

var randomArray = [
   '#cc0000','#00cc00', '#0000cc'
];

// use _.sample
var randomElement = _.sample(randomArray);

// manually use _.random
var randomElement = randomArray[_.random(randomArray.length-1)];

Or to shuffle an entire array:

或者打乱整个数组:

// use underscore's shuffle function
var firstRandomElement = _.shuffle(randomArray)[0];

回答by Dino Reic

1. solution: define Array prototype

1.解决方案:定义Array原型

Array.prototype.random = function () {
  return this[Math.floor((Math.random()*this.length))];
}

that will work on inline arrays

这将适用于内联数组

[2,3,5].random()

and of course predefined arrays

当然还有预定义的数组

list = [2,3,5]
list.random()

2. solution: define custom function that accepts list and returns element

2.解决方案:定义接受列表并返回元素的自定义函数

get_random = function (list) {
  return list[Math.floor((Math.random()*list.length))];
} 

get_random([2,3,5])

回答by K-Gun

Here's yet another way:

这是另一种方式:

function rand(items) {
    return items[~~(items.length * Math.random())];
}

回答by Rocket Hazmat

var random = items[Math.floor(Math.random()*items.length)]

回答by planetjones

jQuery is JavaScript! It's just a JavaScript framework. So to find a random item, just use plain old JavaScript, for example,

jQuery 就是 JavaScript!它只是一个 JavaScript 框架。因此,要查找随机项目,只需使用普通的旧 JavaScript,例如,

var randomItem = items[Math.floor(Math.random()*items.length)]

回答by Blindy

var rndval=items[Math.floor(Math.random()*items.length)];

回答by Ivan

// 1. Random shuffle items
items.sort(function() {return 0.5 - Math.random()})

// 2. Get first item
var item = items[0]

Shorter:

更短:

var item = items.sort(function() {return 0.5 - Math.random()})[0];

回答by neebz

var items = Array(523,3452,334,31,...5346);

function rand(min, max) {
  var offset = min;
  var range = (max - min) + 1;

  var randomNumber = Math.floor( Math.random() * range) + offset;
  return randomNumber;
}


randomNumber = rand(0, items.length - 1);

randomItem = items[randomNumber];

credit:

信用:

Javascript Function: Random Number Generator

Javascript 函数:随机数生成器