php date_diff() 期望参数 1 是 DateTimeInterface，给定的字符串

date_diff() expects parameter 1 to be DateTimeInterface, string given

提问by Shele?n Alag

i got this problem and i don't know what to do... they have thesame format

我遇到了这个问题，我不知道该怎么办...它们具有相同的格式

$date_expire = '2014-08-06 00:00:00';
$date1 = date("Y-m-d G:i:s");
$date2 = date_create($date_expire);

$diff = date_diff($date1, $date2); //this line makes error..

回答by Rikesh

Because you are passing string whereas date_diffexpects datetimeobject,

因为您正在传递字符串而date_diff需要datetime对象，

$date_expire = '2014-08-06 00:00:00';    
$date = new DateTime($date_expire);
$now = new DateTime();

echo $date->diff($now)->format("%d days, %h hours and %i minuts");

DEMO.

演示。