正则表达式和 PHP - 将 src 属性与 img 标签隔离
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Regex & PHP - isolate src attribute from img tag
提问by Jeff
With PHP, how can I isolate the contents of the src attribute from $foo? The end result I'm looking for would give me just "http://example.com/img/image.jpg"
使用 PHP，如何将 src 属性的内容与 $foo 隔离？我正在寻找的最终结果只会给我“ http://example.com/img/image.jpg”
$foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />';
回答by John Parker
If you don't wish to use regex (or any non-standard PHP components), a reasonable solution using the built-in DOMDocument classwould be as follows:
如果您不想使用正则表达式（或任何非标准 PHP 组件），使用内置DOMDocument 类的合理解决方案如下：
<?php
$doc = new DOMDocument();
$doc->loadHTML('<img src="http://example.com/img/image.jpg" ... />');
$imageTags = $doc->getElementsByTagName('img');
foreach($imageTags as $tag) {
echo $tag->getAttribute('src');
}
?>
回答by St.Woland
Code
代码
<?php
$foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />';
$array = array();
preg_match( '/src="([^"]*)"/i', $foo, $array ) ;
print_r( $array[1] ) ;
Output
输出
http://example.com/img/image.jpg
回答by AntonioCS
I got this code:
我得到了这个代码：
$dom = new DOMDocument();
$dom->loadHTML($img);
echo $dom->getElementsByTagName('img')->item(0)->getAttribute('src');
Assuming there is only one img :P
假设只有一个 img :P
回答by karim79
// Create DOM from string
$html = str_get_html('<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />');
// echo the src attribute
echo $html->find('img', 0)->src;
回答by Josh Janusch
I'm extremely late to this, but I have a simple solution not yet mentioned. Load it with simplexml_load_string(if you have simplexml enabled) and then flip it through json_encodeand json_decode.
我对此非常晚，但我有一个尚未提及的简单解决方案。加载它simplexml_load_string（如果您启用了 simplexml），然后通过json_encode和翻转它json_decode。
$foo = '<img class="foo bar test" title="test image" src="http://example.com/img/image.jpg" alt="test image" width="100" height="100" />';
$parsedFoo = json_decode(json_encode(simplexml_load_string($foo)), true);
var_dump($parsedFoo['@attributes']['src']); // output: "http://example.com/img/image.jpg"
$parsedFoocomes through as
$parsedFoo通过作为
array(1) {
["@attributes"]=>
array(6) {
["class"]=>
string(12) "foo bar test"
["title"]=>
string(10) "test image"
["src"]=>
string(32) "http://example.com/img/image.jpg"
["alt"]=>
string(10) "test image"
["width"]=>
string(3) "100"
["height"]=>
string(3) "100"
}
}
I've been using this for parsing XML and HTML for a few months now and it works pretty well. I've had no hiccups yet, though I haven't had to parse a large file with it (I imagine using json_encodeand json_decodelike that will get slower the larger the input gets). It's convoluted, but it's by far the easiest way to read HTML properties.
几个月来，我一直在使用它来解析 XML 和 HTML，而且效果很好。我已经没有打嗝呢，虽然我还没有解析它一个大文件（我想象使用json_encode和json_decode喜欢，将得到较慢的输入变得更大）。这很复杂，但它是迄今为止读取 HTML 属性的最简单方法。
回答by WNRosenberg
preg_matchsolves this problem nicely.
preg_match很好的解决了这个问题。
See my answer here: How to extract img src, title and alt from html using php?
在此处查看我的答案：如何使用 php 从 html 中提取 img src、title 和 alt？
回答by Jeff
Here's what I ended up doing, although I'm not sure about how efficient this is:
这是我最终做的，虽然我不确定这有多有效：
$imgsplit = explode('"',$data);
foreach ($imgsplit as $item) {
if (strpos($item, 'http') !== FALSE) {
$image = $item;
break;
}
}
回答by Joel A. Villarreal Bertoldi
You can go around this problem using this function:
您可以使用此功能解决此问题：
function getTextBetween($start, $end, $text)
{
$start_from = strpos($text, $start);
$start_pos = $start_from + strlen($start);
$end_pos = strpos($text, $end, $start_pos + 1);
$subtext = substr($text, $start_pos, $end_pos);
return $subtext;
}
$foo = '<img class="foo bar test" title="test image"
src="http://example.com/img/image.jpg" alt="test image"
width="100" height="100" />';
$img_src = getTextBetween('src="', '"', $foo);
回答by user256058
try this pattern:
试试这个模式：
'/< \s* img [^\>]* src \s* = \s* [\""\']? ( [^\""\'\s>]* )/'
回答by Oni Victor
lets assume i use
让我们假设我使用
$text ='<img src="blabla.jpg" alt="blabla" />';
in
在
getTextBetween('src="','"',$text);
the codes will return :
代码将返回：
blabla.jpg" alt="blabla"
which is wrong, we want the codes to return the text between the attribute value quotes i.e attr = "value".
这是错误的，我们希望代码返回属性值引号之间的文本，即 attr = "value"。
so
所以
function getTextBetween($start, $end, $text)
{
// explode the start string
$first_strip= end(explode($start,$text,2));
// explode the end string
$final_strip = explode($end,$first_strip)[0];
return $final_strip;
}
does the trick!.
有诀窍！。
Try
尝试
getTextBetween('src="','"',$text);
will return:
将返回：
blabla.jpg
Thanks all the same , because your solution gave me an insight to the final solution .
同样感谢，因为您的解决方案让我对最终解决方案有了深入的了解。
