php In_array 不起作用
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In_array not working
提问by DeDevelopers
I have an array, I applied in_array function to find a specific number in that array, but it's showing no result, the data is inside the array but no response..:(
我有一个数组，我应用 in_array 函数在该数组中查找特定数字，但没有显示结果，数据在数组内但没有响应..:(
Array:
大批：
Array
(
[0] => SimpleXMLElement Object
(
[0] => 572140
)
[1] => SimpleXMLElement Object
(
[0] => 533167
)
[2] => SimpleXMLElement Object
(
[0] => 572070
)
[3] => SimpleXMLElement Object
(
[0] => 572383
)
[4] => SimpleXMLElement Object
(
[0] => 285078
)
[5] => SimpleXMLElement Object
(
[0] => 430634
)
}
CODE I AM USING:
我正在使用的代码：
if(in_array('285078',$arr))
{
echo 'yes';
}
else
{
echo "No";
}
This is the array I am creating from the xml file..
这是我从 xml 文件创建的数组。
$arr = array();
foreach($xmlInjury as $data)
{
array_push($arr,$data->player_id);
}
It's only showing 'NO'.. please help me on this...
它只显示“不”……请帮我解决这个问题……
回答by Kevin
You need to cast them all first, then search. Like this:
您需要先将它们全部投射，然后进行搜索。像这样：
$new_arr = array_map(function($piece){
return (string) $piece;
}, $arr);
// then use in array
if(in_array('285078', $new_arr)) {
echo 'exists';
} else {
echo 'does not exists';
}
回答by u_mulder
First, your array is not array of strings, it's array of objects. If you can't change the structure of array try this:
首先，您的数组不是字符串数组，而是对象数组。如果你不能改变数组的结构试试这个：
foreach ($your_array as $item) {
if (strval($item) == '25478') {
echo 'found!';
break;
}
}
If you can change your array, add items to it like this:
如果您可以更改数组，请像这样向其中添加项目：
$your_array[] = strval($appended_value);
After that you can use in_array.
之后，您可以使用in_array.
回答by Luká? Rutar
in_array is not recursive, it searches only on first level. and first level member of you array are SimpleXMLElement Objects, not an numbers.
in_array 不是递归的，它只在第一级搜索。数组的第一级成员是 SimpleXMLElement 对象，而不是数字。
回答by Khushboo
Try with typecasting your array :-
尝试对数组进行类型转换：-
$array = (array) $yourarray;
if(in_array('285078',$arr))
{
echo 'yes';
}
else
{
echo "No";
}
