Ruby-on-rails Rails：“新建或编辑”路径助手？
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Rails: "new or edit" path helper?
提问by Andrew
Is there a simple and straightforward way to provide a link in a view to either create a resource if it doesn't exist or edit the existing on if it does?
是否有一种简单而直接的方法可以在视图中提供链接，以便在资源不存在时创建资源或在存在时编辑现有资源？
IE:
IE：
User has_one :profile
Currently I would be doing something like...
目前我会做类似的事情......
-if current_user.profile?
= link_to 'Edit Profile', edit_profile_path(current_user.profile)
-else
= link_to 'Create Profile', new_profile_path
This is ok if it's the only way, but I've been trying to see if there's a "Rails Way" to do something like:
如果这是唯一的方法，这还可以，但是我一直在尝试查看是否有“Rails 方式”可以执行以下操作：
= link_to 'Manage Profile', new_or_edit_path(current_user.profile)
Is there any nice clean way to do something like that? Something like the view equivalent of Model.find_or_create_by_attribute(....)
有什么好的干净的方法来做这样的事情吗？类似于视图的东西Model.find_or_create_by_attribute(....)
回答by Douglas F Shearer
Write a helper to encapsulate the more complex part of the logic, then your views can be clean.
写一个助手来封装逻辑中更复杂的部分，然后你的视图就可以干净了。
# profile_helper.rb
module ProfileHelper
def new_or_edit_profile_path(profile)
profile ? edit_profile_path(profile) : new_profile_path(profile)
end
end
Now in your views:
现在在你看来：
link_to 'Manage Profile', new_or_edit_profile_path(current_user.profile)
回答by Russell
I came across this same problem, but had a lot of models I wanted to do it for. It seemed tedious to have to write a new helper for each one so I came up with this:
我遇到了同样的问题，但我有很多模型想要这样做。必须为每个助手编写一个新助手似乎很乏味，所以我想出了这个：
def new_or_edit_path(model_type)
if @parent.send(model_type)
send("edit_#{model_type.to_s}_path", @parent.send(model_type))
else
send("new_#{model_type.to_s}_path", :parent_id => @parent.id)
end
end
Then you can just call new_or_edit_path :childfor any child of the parent model.
然后您可以调用new_or_edit_path :child父模型的任何子模型。
回答by krunal shah
Another way!
其它的办法！
<%=
link_to_if(current_user.profile?, "Edit Profile",edit_profile_path(current_user.profile)) do
link_to('Create Profile', new_profile_path)
end
%>
回答by MurifoX
If you want a generic way:
如果你想要一个通用的方式：
def new_or_edit_path(model)
model.new_record? ? send("new_#{model.model_name.singular}_path", model) : send("edit_#{model.model_name.singular}_path", model)
end
Where modelis your instance variable on your view. Example:
model您的视图中的实例变量在哪里。例子：
# new.html.erb from users
<%= link_to new_or_edit_path(@user) do %>Clear Form<% end %>
回答by gandham varesh kumar
Try this:
尝试这个：
module ProfilesHelper
def new_or_edit_profile_path(profile)
profile ? edit_profile_path(profile) : new_profile_path(profile)
end
end
and with your link like:
并使用您的链接：
<%= link_to 'Manage Profile', new_or_edit_profile_path(@user.profile) %>
