javascript 正则表达式过滤掉某些字符
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/31885080/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Regex to filter out certain characters
提问by Mike. D
What would a regex string look like if you were provided a random string such as :
如果为您提供了一个随机字符串，那么正则表达式字符串会是什么样子，例如：
"u23ntfb23nnfj3mimowmndnwm8"
“u23ntfb23nnfj3mimowmndnwm8”
and I wanted to filter out certain characters such as 2, b, j, d, g, k and 8?
我想过滤掉某些字符，例如 2、b、j、d、g、k 和 8？
So in this case, the function would return '2bjd8'.
所以在这种情况下，函数将返回'2bjd8'.
There's a lot of literature on the internet but nothing straight to the point. It shouldn't be too hard to create a regex to filter the string right?
互联网上有很多文献，但没有什么是直截了当的。创建一个正则表达式来过滤字符串应该不会太难吧？
ps. this is not homework but I am cool with daft punk
附：这不是作业，但我对愚蠢的朋克很酷
回答by cн?dk
You need to create a regular expression first and then execute it over your string.
您需要先创建一个正则表达式，然后在您的string.
This is what you need :
这是你需要的：
var str = "u23ntfb23nnfj3mimowmndnwm8";
var re = /[2bjd8]+/g;
alert((str.match(re) || []).join(''));To get all the matches use String.prototype.match()with your Regex.
要获得所有匹配项String.prototype.match()，请使用您的 Regex。
It will give you the following matches in output:
它将在输出中为您提供以下匹配项：
2 b2 j d 8
2 b2 jd 8
回答by hwnd
You could use a character class to define the characters.
您可以使用字符类来定义字符。
Using the match()method to analyze the string and then filter out the duplicates.
使用该match()方法对字符串进行分析，然后过滤掉重复项。
function filterbychr(str) {
var regex = /[28bdgjk]/g
return str.match(regex).filter(function(m,i,self) {
return i == self.indexOf(m)
}).join('')
}
var result = filterbychr('u23ntfb23nnfj3mimowmndnwm8') //=> "2bjd8"
