asp.net-mvc 如何将参数传递给 ASP.NET MVC 中的局部视图？
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How to pass parameters to a partial view in ASP.NET MVC?
提问by Saeed Neamati
Suppose that I have this partial view:
假设我有这个部分观点：
Your name is <strong>@firstName @lastName</strong>
which is accessible through a child only action like:
可通过仅限儿童的操作访问，例如：
[ChildActionOnly]
public ActionResult FullName(string firstName, string lastName)
{
}
And I want to use this partial view inside another view with:
我想在另一个视图中使用这个局部视图：
@Html.RenderPartial("FullName")
In other words, I want to be able to pass firstName ans lastName from view to partial view. How should I do that?
换句话说，我希望能够将 firstName 和 lastName 从视图传递到局部视图。我该怎么做？
采纳答案by David Wick
Use this overload (RenderPartialExtensions.RenderPartialon MSDN):
使用此重载（RenderPartialExtensions.RenderPartial在 MSDN 上）：
public static void RenderPartial(
this HtmlHelper htmlHelper,
string partialViewName,
Object model
)
so:
所以：
@{Html.RenderPartial(
"FullName",
new { firstName = model.FirstName, lastName = model.LastName});
}
回答by Garry English
Here is another way to do it if you want to use ViewData:
如果您想使用 ViewData，这是另一种方法：
@Html.Partial("~/PathToYourView.cshtml", null, new ViewDataDictionary { { "VariableName", "some value" } })
And to retrieve the passed in values:
并检索传入的值：
@{
string valuePassedIn = this.ViewData.ContainsKey("VariableName") ? this.ViewData["VariableName"].ToString() : string.Empty;
}
回答by simonlchilds
You need to create a view model. Something like this should do...
您需要创建一个视图模型。这样的事情应该做...
public class FullNameViewModel
{
public string FirstName { get; set; }
public string LastName { get; set; }
public FullNameViewModel() { }
public FullNameViewModel(string firstName, string lastName)
{
this.FirstName = firstName;
this.LastName = lastName;
}
}
then from your action result pass the model
然后从您的操作结果传递模型
return View("FullName", new FullNameViewModel("John", "Doe"));
and you will be able to access @Model.FirstNameand @Model.LastNameaccordingly.
你将能够访问@Model.FirstName和@Model.LastName相应。
回答by BlackTigerX
make sure you add {} around Html.RenderPartial, as:
确保在 Html.RenderPartial 周围添加 {}，如：
@{Html.RenderPartial("FullName", new { firstName = model.FirstName, lastName = model.LastName});}
not
不是
@Html.RenderPartial("FullName", new { firstName = model.FirstName, lastName = model.LastName});
回答by lakesare
Following is working for me on dotnet 1.0.1:
以下在dotnet 1.0.1上对我来说有效：
./ourView.cshtml
./ourView.cshtml
@Html.Partial(
"_ourPartial.cshtml",
new ViewDataDictionary(this.Vi??ewData) {
{
"hi", "hello"
}
}
);
./_ourPartial.cshtml
./_ourPartial.cshtml
<h1>@this.ViewData["hi"]</h1>
回答by Cássio Batista Pereira
Just:
只是：
@Html.Partial("PartialName", Model);
