在 jQuery 选择器中连接
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Concatenate in jQuery Selector
提问by jason328
Simple problem. I have a js variable I want to be concatenated too within a jQuery selector. However it is not working. No errors are popping up either. What is wrong? How do I correctly concatenate a variable to some text in a jQuery selector.
简单的问题。我有一个 js 变量，我也想在 jQuery 选择器中进行连接。但是它不起作用。也没有出现错误。怎么了？如何正确地将变量连接到 jQuery 选择器中的某些文本。
<div id="part2"></div>
<script type="text/javascript" >
$('#button').click(function ()
{
var text = $('#text').val();
var number = 2;
$.post('ajaxskeleton.php', {
red: text
},
function(){
$('#part' + number).html(text);
});
});
</script>
回答by sabithpocker
There is nothing wrong with syntax of
的语法没有任何问题
$('#part' + number).html(text);
jQuery accepts a String (usually a CSS Selector) or a DOM Nodeas parameter to create a jQuery Object.
jQuery 接受一个字符串（通常是一个 CSS 选择器）或一个DOM 节点作为参数来创建一个jQuery 对象。
In your case you should pass a String to $()that is
在您的情况下，您应该将一个字符串传递给$()它
$(<a string>)
Make sure you have access to the variables numberand text.
确保您可以访问变量number和text.
To test do:
测试做：
function(){
alert(number + ":" + text);//or use console.log(number + ":" + text)
$('#part' + number).html(text);
});
If you see you dont have access, pass them as parameters to the function, you have to include the uual parameters for $.get and pass the custom parameters after them.
如果您发现您无权访问，请将它们作为参数传递给函数，您必须包含 $.get 的 uual 参数并在它们之后传递自定义参数。
回答by Alnitak
Your concatenation syntax is correct.
您的连接语法是正确的。
Most likely the callback function isn't even being called. You can test that by putting an alert(), console.log()or debuggerline in that function.
很可能甚至没有调用回调函数。您可以通过在该函数中放置alert(),console.log()或debuggerline来测试它。
If it isn't being called, most likely there's an AJAX error. Look at chaining a .fail()handler after $.post()to find out what the error is, e.g.:
如果它没有被调用，很可能是 AJAX 错误。查看链接.fail()处理程序之后$.post()找出错误是什么，例如：
$.post('ajaxskeleton.php', {
red: text
}, function(){
$('#part' + number).html(text);
}).fail(function(jqXHR, textStatus, errorThrown) {
console.log(arguments);
});
