Javascript:将(十六进制)有符号整数转换为 javascript 值

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时间:2020-10-26 18:52:26  来源:igfitidea点击:

Javascript: convert a (hex) signed integer to a javascript value

javascriptsign

提问by mythbu

I have a signed value given as a hex number, by example 0xffeband want convert it into -21as a "normal" Javascript integer.

例如,我有一个以十六进制数给出的有符号值,0xffeb并希望将其转换-21为“正常”Javascript 整数。

I have written some code so far:

到目前为止,我已经编写了一些代码:

function toBinary(a) { //: String
    var r = '';
    var binCounter = 0;
    while (a > 0) {
        r = a%2 + r;
        a = Math.floor(a/2);
    }
    return r;
}

function twoscompl(a) { //: int
    var l = toBinaryFill(a).length;
    var msb = a >>> (l-1);

    if (msb == 0) {
        return a;
    }

    a = a-1;
    var str = toBinary(a);
    var nstr = '';
    for (var i = 0; i < str.length; i++) {
        nstr += str.charAt(i) == '1' ? '0' : '1';
    }
    return (-1)*parseInt(nstr);
}

The problem is, that my function returns 1 as MSB for both numbers because only at the MSB of the binary representation "string" is looked. And for this case both numbers are 1:

问题是,我的函数对于两个数字都返回 1 作为 MSB,因为只在二进制表示形式“字符串”的 MSB 处查看。对于这种情况,两个数字都是 1:

-21 => 0xffeb => 1111 1111 1110 1011
 21 => 0x15   =>              1 0101

Have you any idea to implement this more efficient and nicer?

你有什么想法来实现这个更有效和更好的吗?

Greetings, mythbu

问候,神话

回答by Bart Friederichs

Use parseInt()to convert (which just accepts your hex string):

使用parseInt()转换(这只是接受你的十六进制字符串):

parseInt(a);

Then use a mask to figure out if the MSB is set:

然后使用掩码确定是否设置了 MSB:

a & 0x8000

If that returns a nonzero value, you know it is negative.

如果它返回一个非零值,你就知道它是负数。

To wrap it all up:

总结一下:

a = "0xffeb";
a = parseInt(a, 16);
if ((a & 0x8000) > 0) {
   a = a - 0x10000;
}

Note that this only works for 16-bit integers (shortin C). If you have a 32-bit integer, you'll need a different mask and subtraction.

请注意,这仅适用于 16 位整数(short在 C 中)。如果您有一个 32 位整数,则需要不同的掩码和减法。

回答by milosmns

I came up with this

我想出了这个

function hexToInt(hex) {
    if (hex.length % 2 != 0) {
        hex = "0" + hex;
    }
    var num = parseInt(hex, 16);
    var maxVal = Math.pow(2, hex.length / 2 * 8);
    if (num > maxVal / 2 - 1) {
        num = num - maxVal
    }
    return num;
}

And usage:

和用法:

var res = hexToInt("FF"); // -1
res = hexToInt("A"); // same as "0A", 10
res = hexToInt("FFF"); // same as "0FFF", 4095
res = hexToInt("FFFF"); // -1

So basically the hex conversion range depends on hex's length, ant this is what I was looking for. Hope it helps.

所以基本上十六进制转换范围取决于十六进制的长度,这就是我要找的。希望能帮助到你。

回答by Kostynha

Based on @Bart FriederichsI've come with:

基于@ Bart Friederichs我来了:

function HexToSignedInt(num, numSize) {
    var val = {
        mask: 0x8 * Math.pow(16, numSize-1), //  0x8000 if numSize = 4
        sub: -0x1 * Math.pow(16, numSize)    //-0x10000 if numSize = 4
    }
    if(parseInt(num, 16) & val.mask > 0) { //negative
        return (val.sub + parseInt(num, 16))
    }else {                                 //positive
        return (parseInt(num,16))
    }
 }

so now you can specify the exact length (in nibbles).

所以现在您可以指定确切的长度(以半字节为单位)。

var numberToConvert = "CB8";
HexToSignedInt(numberToConvert, 3);
//expected output: -840

回答by Kitani Islam

function hexToSignedInt(hex) {
    if (hex.length % 2 != 0) {
        hex = "0" + hex;
    }
    var num = parseInt(hex, 16);
    var maxVal = Math.pow(2, hex.length / 2 * 8);
    if (num > maxVal / 2 - 1) {
        num = num - maxVal
    }
    return num;
}

function hexToUnsignedInt(hex){
    return parseInt(hex,16);
}

the first for signed integer and the second for unsigned integer

第一个用于有符号整数,第二个用于无符号整数