java Java替换特殊字符
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Java replacing special characters
提问by Jammy
I'm trying to replace special characters in a file with a pattern with only special characters, but it doesn't seem to be working.
我正在尝试用仅包含特殊字符的模式替换文件中的特殊字符，但它似乎不起作用。
String special = "Something @$ great @$ that.";
special = special.replaceAll("@$", "as");
However, when I run that I get the original string instead of the replaced string. What am I doing wrong?
但是，当我运行它时，我得到的是原始字符串而不是替换后的字符串。我究竟做错了什么？
回答by Nicolas Filotto
Simply use String#replace(CharSequence target, CharSequence replacement)in your case to replace a given CharSequence, as next:
只需String#replace(CharSequence target, CharSequence replacement)在您的情况下使用来替换给定的CharSequence，如下所示：
special = special.replace("@$", "as");
Or use Pattern.quote(String s)to convert your Stringas a literal pattern String, as next:
或用于Pattern.quote(String s)将您的转换String为文字模式String，如下所示：
special = special.replaceAll(Pattern.quote("@$"), "as");
If you intend to do it very frequently, consider reusing the corresponding Patterninstance (the class Patternis thread-safe which means that you can share instances of this class) to avoid compiling your regular expression at each call which has a price in term of performances.
如果您打算非常频繁地执行此操作，请考虑重用相应的Pattern实例（该类Pattern是线程安全的，这意味着您可以共享该类的实例）以避免在每次调用时编译正则表达式，这会影响性能。
So your code could be:
所以你的代码可能是：
private static final Pattern PATTERN = Pattern.compile("@$", Pattern.LITERAL);
...
special = PATTERN.matcher(special).replaceAll("as");
回答by Mritunjay
Escape characters:-
转义字符：-
String special = "Something @$ great @$ that.";
special = special.replaceAll("@\$", "as");
System.out.println(special);
For Regular Expression, below 12 characters are reserved called as metacharacters. If you want to use any of these characters as a literal in a regex, you need to escape them with a backslash.
对于正则表达式，保留 12 个以下的字符称为元字符。如果要将这些字符中的任何一个用作正则表达式中的文字，则需要使用反斜杠将它们转义。
the backslash \
the caret ^
the dollar sign $
the period or dot .
the vertical bar or pipe symbol |
the question mark ?
the asterisk or star *
the plus sign +
the opening parenthesis (
the closing parenthesis )
the opening square bracket [
and the opening curly brace {
references:- http://www.regular-expressions.info/characters.html
回答by AdamK
The method replaceAll accepts regex as a pattern to substitue: http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#replaceAll(java.lang.String,%20java.lang.String)
方法 replaceAll 接受正则表达式作为替换模式：http://docs.oracle.com/javase/7/docs/api/java/lang/String.html#replaceAll(java.lang.String,%20java.lang .细绳）
Try simply:
简单地尝试：
special = special.replace("@$", "as");
回答by Syed Salman Hassan
String special = "Something @$ great @$ that.";
System.out.println(special.replaceAll("[@][$]", "as"));
it should be like this.
它应该是这样的。
回答by Anneli Manneli
special = special.replaceAll("\W","as");
works with all special characters.
适用于所有特殊字符。
回答by Robin Lack
Note that the first given parameter is not a string you want replace. It is a regular expression. You can try to build a regular expression that matches the string you want to replace on this site.
请注意，第一个给定的参数不是您要替换的字符串。它是一个正则表达式。你可以尝试建立要替换字符串相匹配的正则表达式上这个网站。
special = special.replaceAll("\\@\\$", "as");would work, as suggested by @Mritunjay
special = special.replaceAll("\\@\\$", "as");会起作用，正如@Mritunjay 所建议的那样
