php PHP日期转换dd [th/st/rd]/月/yyyy
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PHP date conversion dd [th/st/rd] / month / yyyy
提问by Aliya Kcx
I have my users entering the date in this format :- mm/dd/yyyy (11/21/2012)
我让我的用户以这种格式输入日期：- mm/dd/yyyy (11/21/2012)
My PHP script converts the date into the following format :- dd-Month-yyyy (21-November-2012)
我的 PHP 脚本将日期转换为以下格式：- dd-Month-yyyy (21-November-2012)
I do this using :-
我这样做： -
$new_date = date('d-F-Y', strtotime($user_date));
How can I have the date in this format :- 21st November 2012?
我怎样才能获得这种格式的日期：- 21st November 2012？
Thanks
谢谢
回答by hsz
回答by PHP Ferrari
It will output as you expect
它会像你期望的那样输出
$my_date = '2016-01-01';
echo date('F jS, Y', strtotime($my_date));
# January 1st, 2016
while dSwill also prepends 0
而dS也会在前面加上0
echo date('F dS, Y', strtotime($my_date));
# January 01st, 2016
回答by user9187674
$new_date = date('jS F Y', strtotime($date));
S- English ordinal suffix for the day of the month, 2 characters
(st, nd, rdor th. Works well with j)
S- 月份日期的英文序数后缀，2 个字符（st、nd、rd或th。适用于j）
回答by Kiryamwibo Yenusu
You can use something like:
您可以使用以下内容：
echo date('l, F jS');
Or even get a bit fancy with the HTML:
或者甚至对 HTML 有点花哨：
echo date('l, F j<\s\u\p>S</\s\u\p>');
回答by Nikit Barochiya
**My Date = 22-12-1992**
<?php
$mydate = "22-12-1992";
$newDate = date("d M Y", strtotime($mydate));
$new_date = date('dS F Y', strtotime($newDate));
echo $new_date;
?>
**OutPut = 22nd December 1992**
回答by Karan Shaw
$date = date_create('09-22-2012');by this code you will get your desire
echo $date->format('d S F Y');
$date = date_create('09-22-2012');通过这个代码你会得到你的愿望
echo $date->format('d S F Y');
for more you can also visit http://php.net/manual/en/datetime.formats.date.php
有关更多信息，您还可以访问http://php.net/manual/en/datetime.formats.date.php
