Java中的用户输入字符串和整数

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时间:2020-08-12 17:38:33  来源:igfitidea点击:

user input string and integers in Java

javastringint

提问by Athirah Hazira

    System.out.print("Name : ");
    String name = in.nextLine();

    System.out.print("Age : ");
    int age = in.nextInt();

    System.out.print("City : ");
    String city = in.nextLine();

the output will be :

输出将是:

Name : test

名称 : 测试

Age : 20

年龄 : 20

BUILD SUCCESSFUL

建造成功

when i debug them, it won't read the user input for "city" . but when i changed the data type for "age" to string, it will read. how can i kept the data type of age to int with the system reading the user inputs for city ?

当我调试它们时,它不会读取“城市”的用户输入。但是当我将“age”的数据类型更改为字符串时,它会读取。如何在系统读取城市用户输入的情况下将年龄的数据类型保持为 int ?

采纳答案by Scary Wombat

As there is still a new line character in the buffer after reading the age, change it to..

由于读取年龄后缓冲区中还有一个换行符,将其更改为..

System.out.print("Name : ");
String name = in.nextLine();

System.out.print("Age : ");
int age = in.nextInt();
//add
in.nextLine();

System.out.print("City : ");
String city = in.nextLine();

回答by MadProgrammer

There is still a new line character in the buffer after reading the age. Try adding a in.nextLinebefore you ask for the city value.

读取年龄后缓冲区中仍然有一个换行符。in.nextLine在询问城市值之前尝试添加 a 。

回答by newuser

Try this,

尝试这个,

System.out.print("Age : ");
int age = Integer.parseInt(in.nextLine());