Linux - 替换文件名中的空格
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Linux - Replacing spaces in the file names
提问by Mithun Sreedharan
I have a number of files in a folder, and I want to replace every space character in all file names with underscores. How can I achieve this?
我在一个文件夹中有许多文件，我想用下划线替换所有文件名中的每个空格字符。我怎样才能做到这一点？
采纳答案by neesh
This should do it:
这应该这样做：
for file in *; do mv "$file" `echo $file | tr ' ' '_'` ; done
回答by Arthur Frankel
I believe your answer is in Replace spaces in filenames with underscores.
回答by Amir Afghani
Try something like this, assuming all of your files were .txt's:
尝试这样的事情，假设您的所有文件都是 .txt 的：
for files in *.txt; do mv “$files” `echo $files | tr ‘ ‘ ‘_'`; done
回答by Murali VP
If you use bash:
如果您使用 bash：
for file in *; do mv "$file" ${file// /_}; done
回答by DigitalRoss
Use sh...
使用...
for i in *' '*; do mv "$i" `echo $i | sed -e 's/ /_/g'`; done
If you want to try this out before pulling the trigger just change mvto echo mv.
如果您想在扣动扳机之前尝试一下，只需更改mv为echo mv。
回答by ghostdog74
Quote your variables:
引用你的变量：
for file in *; do echo mv "'$file'" "${file// /_}"; done
Remove the "echo" to do the actual rename.
删除“回声”以进行实际重命名。
回答by DF.
I prefer to use the command 'rename', which takes Perl-style regexes:
我更喜欢使用命令“重命名”，它采用 Perl 风格的正则表达式：
rename "s/ /_/g" *
You can do a dry run with the -n flag:
您可以使用 -n 标志进行试运行：
rename -n "s/ /_/g" *
回答by javipas
What if you want to apply the replace task recursively? How would you do that?
如果您想递归地应用替换任务怎么办？你会怎么做？
Well, I just found the answer myself. Not the most elegant solution, (also tries to rename files that do not comply with the condition) but it works. (BTW, in my case I needed to rename the files with '%20', not with an underscore)
好吧，我只是自己找到了答案。不是最优雅的解决方案，（也尝试重命名不符合条件的文件）但它有效。（顺便说一句，在我的情况下，我需要用“%20”重命名文件，而不是用下划线）
#!/bin/bash
find . -type d | while read N
do
(
cd "$N"
if test "$?" = "0"
then
for file in *; do mv "$file" ${file// /%20}; done
fi
)
done
回答by Desta Haileselassie Hagos
The easiest way to replace a string (space character in your case) with another string in Linuxis using sed. You can do it as follows
用另一个字符串替换字符串（在您的情况下为空格字符）的最简单方法Linux是使用sed. 你可以这样做
sed -i 's/\s/_/g' *
Hope this helps.
希望这可以帮助。
回答by akilesh raj
To rename all the files with a .pyextension use,
find . -iname "*.py" -type f | xargs -I% rename "s/ /_/g" "%"
要.py使用扩展名重命名所有文件，
find . -iname "*.py" -type f | xargs -I% rename "s/ /_/g" "%"
Sample output,
样本输出，
$ find . -iname "*.py" -type f
./Sample File.py
./Sample/Sample File.py
$ find . -iname "*.py" -type f | xargs -I% rename "s/ /_/g" "%"
$ find . -iname "*.py" -type f
./Sample/Sample_File.py
./Sample_File.py
