xcode 如何检查 *number* 是否在数组中
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How to check if *number* is in a array
提问by Emil
Pretty basic programming question, I know PHP have a function for it, but does the iPhone OS have one?
相当基本的编程问题，我知道 PHP 有一个功能，但 iPhone 操作系统有吗？
I want to check if the current indexPath is a value in an array.
我想检查当前的 indexPath 是否是数组中的值。
PHP Example:
PHP 示例：
<?php
$indexPath = 3;
$array = array("0", "1", "2", "3", "4");
if (in_array($indexPath, $array)) {
// Do something
}
?>
Does anybody know how to do the same thing in iOS?
有人知道如何在 iOS 中做同样的事情吗？
回答by prendio2
containsObject:
Returns a Boolean value that indicates whether a given object is present in the receiver.
- (BOOL)containsObject:(id)anObject
containsObject：
返回一个布尔值，指示接收器中是否存在给定对象。
- (BOOL)containsObject:(id)anObject
For example:
例如：
if ([arrayofNumbers containsObject:[NSNumber numberWithInt:516]])
NSLog(@"WIN");
or to check an indexPath:
或检查索引路径：
if ([arrayofIndexPaths containsObject:indexPath])
NSLog(@"Yup, we have it");
I should clarify that an NSIndexPathis not a number but a series of numbers that "represents the path to a specific node in a tree of nested array collections" as explained in more detail in the developer documentation.
我应该澄清一下， anNSIndexPath不是数字，而是一系列数字，“代表嵌套数组集合树中特定节点的路径”，如开发人员文档中更详细的解释。
回答by Jeff B
You want containsObjector indexOfObject:
你想要containsObject或indexOfObject：
unsigned int myIndex = [myArray indexOfObject: [NSNumber numberWithInt: 3]];
if(myIndex != NSNotFound) {
// Do something with myIndex
}
Or:
或者：
if([myArray containsObject: [NSNumber numberWithInt: 3]]) {
// Just need to know if it's there...
}
