Python：获取列表中字典项的索引
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Python: Get index of dictionary item in list
提问by dkgirl
I have a list li:
我有一个列表 li：
[
{name: "Tom", age: 10},
{name: "Mark", age: 5},
{name: "Pam", age: 7}
]
I want to get the index of the item that has a certain name. For example, if I ask for "Tom" it should give me: 0. "Pam" should give me 2.
我想获取具有特定名称的项目的索引。例如，如果我要求“Tom”，它应该给我：0。“Pam”应该给我 2。
回答by satoru
You may index the dicts by name
您可以通过以下方式索引字典 name
people = [ {'name': "Tom", 'age': 10}, {'name': "Mark", 'age': 5} ]
name_indexer = dict((p['name'], i) for i, p in enumerate(people))
name_indexer.get('Tom', -1)
回答by John La Rooy
>>> from operator import itemgetter
>>> map(itemgetter('name'), li).index('Tom')
0
>>> map(itemgetter('name'), li).index('Pam')
2
If you need to look up a lot of these from the same list, creating a dict as done in Satoru.Logic's answer, is going to be a lot more efficent
如果您需要从同一个列表中查找很多这些，按照 Satoru.Logic 的答案创建一个 dict 会更有效率
