C# HttpWebRequest 错误：503 服务器不可用
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HttpWebRequest Error: 503 server unavailable
提问by Ainun Nuha
I'm using HttpWebRequest and I get error when execute GetResponse().
我正在使用 HttpWebRequest 并且在执行 GetResponse() 时出现错误。
I using this code:
我使用此代码：
private void button1_Click(object sender, EventArgs e)
{
Uri myUri = new Uri("http://www.google.com/sorry/?continue=http://www.google.com/search%3Fq%3Dyamaha");
// Create a 'HttpWebRequest' object for the specified url.
HttpWebRequest myHttpWebRequest = (HttpWebRequest)WebRequest.Create(myUri);
// Set the user agent as if we were a web browser
myHttpWebRequest.UserAgent = @"Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.0.4) Gecko/20060508 Firefox/1.5.0.4";
HttpWebResponse myHttpWebResponse = (HttpWebResponse)myHttpWebRequest.GetResponse();
var stream = myHttpWebResponse.GetResponseStream();
var reader = new StreamReader(stream);
var html = reader.ReadToEnd();
// Release resources of response object.
myHttpWebResponse.Close();
textBox1.Text = html;
}
采纳答案by Cristian Lupascu
The server really returns a 503 HTTP status code. However, it also returns a response body along with the 503 error condition (the contents you see in a browser if you open that URL).
服务器确实返回了 503 HTTP 状态代码。但是，它还返回响应正文以及 503 错误条件（如果您打开该 URL，您在浏览器中看到的内容）。
You have access to the response in the exception's Responseproperty (in case there's a 503 response, the exception that's raised is a WebException, which has a Responseproperty). you need to catch this exception and handle it properly
您可以访问异常Response属性中的响应（如果有 503 响应，引发的异常是 a WebException，它有一个Response属性）。您需要捕获此异常并正确处理它
Concretely, your code could look like this:
具体来说，您的代码可能如下所示：
string html;
try
{
var myUri = new Uri("http://www.google.com/sorry/?continue=http://www.google.com/search%3Fq%3Dyamaha");
// Create a 'HttpWebRequest' object for the specified url.
var myHttpWebRequest = (HttpWebRequest)WebRequest.Create(myUri);
// Set the user agent as if we were a web browser
myHttpWebRequest.UserAgent = @"Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.0.4) Gecko/20060508 Firefox/1.5.0.4";
var myHttpWebResponse = (HttpWebResponse)myHttpWebRequest.GetResponse();
var stream = myHttpWebResponse.GetResponseStream();
var reader = new StreamReader(stream);
html = reader.ReadToEnd();
// Release resources of response object.
myHttpWebResponse.Close();
}
catch (WebException ex)
{
using(var sr = new StreamReader(ex.Response.GetResponseStream()))
html = sr.ReadToEnd();
}
textBox1.Text = html;
