替换java中字符串中所有出现的字符？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/19599341/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
replace all occurrences of a character in a string in java?
提问by frazman
A very noob question..
一个非常菜鸟的问题..
I want to replace all the occurance of "." in a string with empty space..
我想替换所有出现的“。” 在一个有空格的字符串中..
So this is what I tried
所以这就是我尝试过的
String s = "1.2.3.4";
System.out.println(s);
s = s.replaceAll(".", " ");
System.out.println(s);
But the second print is an empty print?
但是第二个打印是空打印？
What did i missed here?
我在这里错过了什么？
采纳答案by Terry Li
You want to escape the .. Otherwise, it can match anything.
你想逃避.. 否则，它可以匹配任何东西。
Try s.replaceAll("\\.", " ")instead.
试试吧s.replaceAll("\\.", " ")。
回答by Evgeniy Dorofeev
Use String.replace(char, char) instead of String.replaceAll
使用 String.replace(char, char) 而不是 String.replaceAll
