xcode 如何在框架内读取资源文件？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/17505856/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to read resources files within a framework?
提问by Lingfeng Xiong
I built a framework and a cocoa application in Mac OS X. The framework is dynamically linked to the application. In a class of the framework, I need to read a resource file within this framework's resources folder. The code below
我在 Mac OS X 中构建了一个框架和一个可可应用程序。该框架与应用程序动态链接。在框架的一个类中，我需要读取这个框架的资源文件夹中的资源文件。下面的代码
NSString *resourcePath = [[NSBundle mainBundle] resourcePath];
NSString *characterCodeTable = [resourcePath stringByAppendingPathComponent:@"pymb.txt"];
does not work since "resourcePath" is the path to application's resources folder, not the framework's.
不起作用，因为“resourcePath”是应用程序资源文件夹的路径，而不是框架的。
So how can I access the framework's resource folder in the code in this framework itself?
那么如何在这个框架本身的代码中访问该框架的资源文件夹呢？
BTW: Is there any best practice to organize miscellaneous files in a framework/application bundle?
顺便说一句：是否有任何最佳实践来组织框架/应用程序包中的杂项文件？
回答by mipadi
Instead of calling +[NSBundle mainBundle], call either +[NSBundle bundleWithIdentifier:]or +[NSBundle bundleForClass:]. The former takes an NSStringargument of the framework's indentifier; the latter takes a Classargument of a class provided by the framework. Then, you can call the usual NSBundlepaths as necessary.
不要调用+[NSBundle mainBundle]，而是调用+[NSBundle bundleWithIdentifier:]或+[NSBundle bundleForClass:]。前者接受NSString框架标识符的参数；后者采用Class框架提供的类的参数。然后，您可以NSBundle根据需要调用常用路径。
Full documentation can be found here.
可以在此处找到完整的文档。
回答by loretoparisi
There are several counter and side effects when using solutions like
使用解决方案时有几个反作用和副作用，例如
[NSBundle mainBundle]
or
或者
NSBundle *localBundle = [NSBundle bundleForClass:[myObject class]]
when you app structure is like
当你的应用程序结构就像
MyContainerApp
|------Frameworks/
|-----------------MyFramework.framwork/
|-------------------Resources/
|-------------mydata.json
So, if you can create a bundle file and give it to container app (as a 3rd party framework developer) you can provide this API
因此，如果您可以创建一个包文件并将其提供给容器应用程序（作为 3rd 方框架开发人员），您可以提供此 API
+ (NSBundle *)frameworkBundle {
static NSBundle* frameworkBundle = nil;
static dispatch_once_t predicate;
dispatch_once(&predicate, ^{
NSString* mainBundlePath = [[NSBundle mainBundle] resourcePath];
NSString* frameworkBundlePath = [mainBundlePath stringByAppendingPathComponent:@"YourFrameworkBundle.bundle"];
frameworkBundle = [NSBundle bundleWithPath:frameworkBundlePath];
});
return frameworkBundle;
}
BUT, a very super-easy, and let's say super-efficient solution is the old C header with hexdump
BUT，一个非常简单的，让我们说超级高效的解决方案是带有hexdump的旧 C 头文件
xxd -i mydata.json >> mydata.json.h
This hexdump will generate a header file with these definitions
这个 hexdump 将生成一个包含这些定义的头文件
unsigned char mydata_json[] = {
// hex array
};
and
和
unsigned int mydata_json_len = 32227;
So in your framework or static library you can access to it just
所以在你的框架或静态库中你可以访问它
unsigned char *rawBytes = mydata_json;
NSUInteger dataLen = mydata_json_len;
NSData *serializedData = [NSData dataWithBytesNoCopy:rawBytes length:dataLen freeWhenDone:NO];
then you maybe want to get it into text:
那么你可能想把它变成文本：
NSString* myString = [NSString stringWithUTF8String:[rawBytes bytes]];
And that's it. Happy coding!
就是这样。快乐编码！
