如何使用 python 3.2 生成（和标记）一个随机整数？
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How do I generate (and label) a random integer with python 3.2?
提问by An hero
Okay, so I'm admittedly a newbie to programming, but I can't determine how to get python v3.2 to generate a random positive integer between parameters I've given it. Just so you can understand the context, I'm trying to create a guessing-game where the user inputs parameters (say 1 to 50), and the computer generates a random number between the given numbers. The user would then have to guess the value that the computer has chosen. I've searched long and hard, but all of the solutions I can find only tell one how to get earlier versions of python to generate a random integer. As near as I can tell, v.3.2 changed how to generate and label a random integer. Anyone know how to do this?
好的，所以我承认我是编程的新手，但我无法确定如何让 python v3.2 在我给它的参数之间生成一个随机的正整数。为了让您能够理解上下文，我正在尝试创建一个猜谜游戏，其中用户输入参数（比如 1 到 50），然后计算机在给定数字之间生成一个随机数。然后用户必须猜测计算机选择的值。我已经搜索了很长时间，但我能找到的所有解决方案都只告诉了一个如何让早期版本的 python 生成一个随机整数。据我所知，v.3.2 更改了生成和标记随机整数的方式。有人知道怎么做吗？
回答by unutbu
Use random.randrangeor random.randint(Note the links are to the Python 3k docs).
使用random.randrange或random.randint（注意链接指向 Python 3k 文档）。
In [67]: import random
In [69]: random.randrange(1,10)
Out[69]: 8
回答by Polipizio
You can use randommodule:
您可以使用random模块：
import random
# Random integer >= 5 and < 10
random.randrange(5, 10)
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