C++中具有多个条件的while循环
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While loop with multiple conditions in C++
提问by ConMaki
How would I make a loop that does the loop until one of multiple conditions is met. For example:
我将如何制作一个循环，直到满足多个条件之一为止。例如：
do
{
srand (time(0));
estrength = rand()%100);
srand (time(0));
strength = rand()%100);
} while( ) //either strength or estrength is not equal to 100
Kind of a lame example, but I think you all will understand.
有点蹩脚的例子，但我想你们都会明白的。
I know of &&, but I want it to only meet one of the conditions and move on, not both.
我知道&&，但我希望它只满足其中一个条件并继续前进，而不是同时满足这两个条件。
回答by Daniel Daranas
Use the ||and/or the &&operators to combine your conditions.
使用||和/或&&运算符组合您的条件。
Examples:
例子：
1.
1.
do
{
...
} while (a || b);
will loop while either aor bare true.
将循环而无论a或者b是真实的。
2.
2.
do
{
...
} while (a && b);
will loop while both aand bare true.
将循环而这两个a和b是真实的。
回答by BoBTFish
while ( !a && !b ) // while a is false and b is false
{
// Do something that will eventually make a or b true.
}
Or equivalently
或等效地
while ( !( a || b ) ) // while at least one of them is false
This table of operator precedencewill be useful when creating more complicated logical statements, but I generally recommend bracketing the hell out of it to make your intentions clear.
在创建更复杂的逻辑语句时，此运算符优先级表将很有用，但我通常建议将其括起来以明确您的意图。
If you're feeling theoretical, you might enjoy De Morgan's Laws.
如果您感觉理论化，您可能会喜欢德摩根定律。
回答by flavian
do {
srand (time(0));
estrength = rand()%100);
srand (time(0));
strength = rand()%100);
} while(!estrength == 100 && !strength == 100 )
回答by broetchen
do {
// ...
} while (strength != 100 || estrength != 100)
