php 读取txt文件的每一行到新的数组元素
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Read each line of txt file to new array element
提问by Dan
I am trying to read every line of a text file into an array and have each line in a new element.
My code so far.
我试图将文本文件的每一行读入一个数组，并将每一行放在一个新元素中。
我的代码到目前为止。
<?php
$file = fopen("members.txt", "r");
$i = 0;
while (!feof($file)) {
$line_of_text = fgets($file);
$members = explode('\n', $line_of_text);
fclose($file);
?>
回答by Yanick Rochon
回答by Drew Dello Stritto
The fastest way that I've found is:
我找到的最快的方法是：
// Open the file
$fp = @fopen($filename, 'r');
// Add each line to an array
if ($fp) {
$array = explode("\n", fread($fp, filesize($filename)));
}
where $filename is going to be the path & name of your file, eg. ../filename.txt.
其中 $filename 将是您的文件的路径和名称，例如。../文件名.txt。
Depending how you've set up your text file, you'll have might have to play around with the \n bit.
根据您设置文本文件的方式，您可能需要使用 \n 位。
回答by RoLife
Just use this:
只需使用这个：
$array = explode("\n", file_get_contents('file.txt'));
回答by iianfumenchu
回答by Gaurav
<?php
$file = fopen("members.txt", "r");
$members = array();
while (!feof($file)) {
$members[] = fgets($file);
}
fclose($file);
var_dump($members);
?>
回答by Rafe Kettler
$lines = array();
while (($line = fgets($file)) !== false)
array_push($lines, $line);
Obviously, you'll need to create a file handle first and store it in $file.
显然，您需要先创建一个文件句柄并将其存储在$file.
回答by CodeBrauer
It's just easy as that:
就这么简单：
$lines = explode("\n", file_get_contents('foo.txt'));
file_get_contents()- gets the whole file as string.
file_get_contents()- 获取整个文件作为字符串。
explode("\n")- will split the string with the delimiter "\n"- what is ASCII-LF escape for a newline.
explode("\n")- 将用分隔符分割字符串"\n"- 换行符的 ASCII-LF 转义是什么。
But pay attention - check that the file has UNIX-Line endings.
但请注意 - 检查文件是否具有UNIX-Line 结尾。
if "\n"will not work properly you have a other coding of2 newline and you can try "\r\n", "\r"or "\025"
如果"\n"不能正常工作，你有一个 2 换行符的其他编码，你可以尝试"\r\n"，"\r"或者"\025"
回答by Attila Nagy
$file = __DIR__."/file1.txt";
$f = fopen($file, "r");
$array1 = array();
while ( $line = fgets($f, 1000) )
{
$nl = mb_strtolower($line,'UTF-8');
$array1[] = $nl;
}
print_r($array);
回答by altayevrim
$file = file("links.txt");
print_r($file);
This will be accept the txt file as array. So write anything to the links.txt file (use one line for one element) after, run this page :) your array will be $file
这将接受 txt 文件作为数组。因此，在运行此页面之后，将任何内容写入 links.txt 文件（一个元素使用一行）：) 您的数组将是 $file
回答by Nick Andren
You were on the right track, but there were some problems with the code you posted. First of all, there was no closing bracket for the while loop. Secondly, $line_of_text would be overwritten with every loop iteration, which is fixed by changing the = to a .= in the loop. Third, you're exploding the literal characters '\n' and not an actual newline; in PHP, single quotes will denote literal characters, but double quotes will actually interpret escaped characters and variables.
您走在正确的轨道上，但是您发布的代码存在一些问题。首先，while 循环没有右括号。其次，每次循环迭代都会覆盖 $line_of_text，这是通过在循环中将 = 更改为 .= 来修复的。第三，您正在分解文字字符 '\n' 而不是实际的换行符；在 PHP 中，单引号将表示文字字符，但双引号实际上会解释转义字符和变量。
<?php
$file = fopen("members.txt", "r");
$i = 0;
while (!feof($file)) {
$line_of_text .= fgets($file);
}
$members = explode("\n", $line_of_text);
fclose($file);
print_r($members);
?>
