如何在 gcc 中使用 C++11 std::stoi？
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How to use C++11 std::stoi with gcc?
提问by Razorfever
Possible Duplicate:
How to convert a number to string and vice versa in C++
可能的重复：
如何在 C++ 中将数字转换为字符串，反之亦然
I am using Qt Creator 2.5.0and gcc 4.7 (Debian 4.7.2-4). I added "QMAKE_CXXFLAGS += -std=c++11" to .pro file. Everything seems to be OK, I used C++11 std::for_each and so on. But when I included "string" header and wanted to use stoi, i got the following error:
我正在使用 Qt Creator 2.5.0和 gcc 4.7（Debian 4.7.2-4）。我在 .pro 文件中添加了“QMAKE_CXXFLAGS += -std=c++11”。一切似乎都很好，我使用了 C++11 std::for_each 等等。但是，当我包含“字符串”标头并想使用 stoi 时，出现以下错误：
performer.cpp:336: error: 'std::string' has no member named 'stoi'
I found some questions related to MinGWand one more, to Eclipse CDTand they had their answers. But I use Linux, why it is NOT working here?
我发现一些相关的问题MinGW的和一个多，到Eclipse CDT的，他们有自己的答案。但是我使用 Linux，为什么它在这里不起作用？
采纳答案by aldo.roman.nurena
#include <iostream>
#include <string>
int main()
{
std::string test = "45";
int myint = stoi(test);
std::cout << myint << '\n';
}
or
或者
#include <iostream>
#include <string>
using namespace std
int main()
{
string test = "45";
int myint = stoi(test);
cout << myint << '\n';
}
look at http://en.cppreference.com/w/cpp/string/basic_string/stol
回答by Mike Seymour
std::stoiis a function at namespace scope, taking a string as its argument:
std::stoi是命名空间范围内的函数，以字符串作为参数：
std::string s = "123";
int i = std::stoi(s);
From the error message, it looks like you expect it to be a member of string, invoked as s.stoi()(or perhaps std::string::stoi(s)); that is not the case. If that's not the problem, then please post the problematic code so we don't need to guess what's wrong with it.
从错误消息来看，您似乎希望它是 的成员string，调用为s.stoi()（或可能std::string::stoi(s)）；事实并非如此。如果那不是问题，那么请发布有问题的代码，这样我们就不需要猜测它出了什么问题。
