php 正则表达式：去除非字母数字或标点符号
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Regex: Strip non alpha numeric or punctuation
提问by Tedd
How can I use PHP to strip out all characters that are NOT alpha, numeric, space, or puncutation?
如何使用 PHP 去除所有非字母、数字、空格或标点符号的字符？
I've tried the following, but it strip punctuation.
我尝试了以下方法，但它去掉了标点符号。
preg_replace("/[^a-zA-Z0-9\s]/", "", $str);
回答by Matthew Flaschen
preg_replace("/[^a-zA-Z0-9\s\p{P}]/", "", $str);
Example:
例子：
php > echo preg_replace("/[^a-zA-Z0-9\s\p{P}]/", "", "?f?oo?. ba?r!");
foo. bar!
\p{P}matches all Unicode punctuation characters (see Unicode character properties). If you only want to allow specific punctuation, simply add them to the negated character class. E.g:
\p{P}匹配所有 Unicode 标点字符（请参阅 Unicode字符属性）。如果您只想允许特定的标点符号，只需将它们添加到否定字符类。例如：
preg_replace("/[^a-zA-Z0-9\s.?!]/", "", $str);
回答by cletus
You're going to have to list the punctuation explicitly as there is no shorthand for that (eg \sis shorthand for white space characters).
您将不得不明确列出标点符号，因为它没有简写（例如\s，空白字符的简写）。
preg_replace('/[^a-zA-Z0-9\s\-=+\|!@#$%^&*()`~\[\]{};:\'",<.>\/?]/', '', $str);
回答by MojganK
$str = trim($str);
$str = trim($str, "\x00..\x1F");
$str = str_replace(array( ""","'","&","<",">"),' ',$str);
$str = preg_replace('/[^0-9a-zA-Z-]/', ' ', $str);
$str = preg_replace('/\s\s+/', ' ', $str);
$str = trim($str);
$str = preg_replace('/[ ]/', '-', $str);
Hope this helps.
希望这可以帮助。
