Java HQL Hibernate 内部连接

HQL Hibernate INNER JOIN

提问by szefu

How can I write this SQL query in Hibernate? I would like to use Hibernate to create queries, not create the database.

如何在 Hibernate 中编写此 SQL 查询？我想使用 Hibernate 创建查询，而不是创建数据库。

SELECT * FROM Employee e INNER JOIN Team t ON e.Id_team=t.Id_team

I created entity classes in SQLServer2008,

我在 SQLServer2008 中创建了实体类，

@Entity
@Table(name="EMPLOYEE")
public class Employee
{
    @Id @GeneratedValue
    @Column(name="ID_EMPLOYEE")
    private int id_employee;
    @Column(name="SURNAME")
    private String surname;
    @Column(name="FIRSTNAME")
    private String firstname;
    @Column(name="ID_PROFESSION")
    private int id_profession;
    @Column(name="ID_BOSS")
    private int id_boss;
    @Column(name="HIRED_DATE")
    private Date hired;
    @Column(name="SALARY")
    private double salary;
    @Column(name="SALARY_ADD")
    private double salary_add;
    @Column(name="ID_TEAM")
    private int id_team;
    //setters and getters
}

@Entity
@Table(name="TEAM")
public class Team
{
    @Id @GeneratedValue
    @Column(name="ID_TEAM")
    private int id_team;
    @Column(name="TEAMNAME")
    private String teamname;
    @Column(name="ADDRESS")
    private String address;
    //setters and getters
}

I tried to build working select query in many ways but it still doesn't work.

我尝试以多种方式构建工作选择查询，但它仍然不起作用。

SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
Session session = sessionFactory.openSession();                 
session.beginTransaction();
String select = "FROM Employee e INNER JOIN Team t ON e.Id_team=t.Id_team";
Query query = session.createQuery(select);
List elist = query.list();
session.getTransaction().commit();
session.close();    

Maybe something is wrong with entities?

也许实体有问题？

采纳答案by JB Nizet

Joins can only be used when there is an association between entities. Your Employee entity should not have a field named id_team, of type int, mapped to a column. It should have a ManyToOne association with the Team entity, mapped as a JoinColumn:

仅当实体之间存在关联时才能使用联接。您的 Employee 实体不应具有映射到列的名为id_team、类型int为 的字段。它应该与 Team 实体有一个 ManyToOne 关联，映射为一个 JoinColumn：

@ManyToOne
@JoinColumn(name="ID_TEAM")
private Team team;

Then, the following query will work flawlessly:

然后，以下查询将完美运行：

select e from Employee e inner join e.team

Which will load all the employees, except those that aren't associated to any team.

这将加载所有员工，除了那些与任何团队无关的员工。

The same goes for all the other fields which are a foreign key to some other table mapped as an entity, of course (id_boss, id_profession).

对于映射为实体的其他表的外键的所有其他字段也是如此，当然 ( id_boss, id_profession)。

It's time for you to read the Hibernate documentation, because you missed an extremely important part of what it is and how it works.

是时候阅读 Hibernate 文档了，因为您错过了它是什么以及它是如何工作的一个非常重要的部分。

回答by Deepak

import java.io.Serializable;
import java.util.ArrayList;
import java.util.List;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.OneToMany;
import javax.persistence.Table;

@Entity
@Table(name="empTable")
public class Employee implements Serializable{
private static final long serialVersionUID = 1L;
private int id;
private String empName;

List<Address> addList=new ArrayList<Address>();


@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
@Column(name="emp_id")
public int getId() {
    return id;
}
public void setId(int id) {
    this.id = id;
}
public String getEmpName() {
    return empName;
}
public void setEmpName(String empName) {
    this.empName = empName;
}

@OneToMany(mappedBy="employee",cascade=CascadeType.ALL)
public List<Address> getAddList() {
    return addList;
}

public void setAddList(List<Address> addList) {
    this.addList = addList;
}
}

We have two entities Employee and Address with One to Many relationship.

我们有两个实体 Employee 和 Address 具有一对多的关系。

import java.io.Serializable;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.Table;

@Entity
@Table(name="address")
public class Address implements Serializable{

private static final long serialVersionUID = 1L;

private int address_id;
private String address;
Employee employee;

@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
public int getAddress_id() {
    return address_id;
}
public void setAddress_id(int address_id) {
    this.address_id = address_id;
}
public String getAddress() {
    return address;
}
public void setAddress(String address) {
    this.address = address;
}

@ManyToOne
@JoinColumn(name="emp_id")
public Employee getEmployee() {
    return employee;
}
public void setEmployee(Employee employee) {
    this.employee = employee;
}
}

By this way we can implement inner join between two tables

这样我们就可以实现两个表之间的内连接

import java.util.List;
import org.hibernate.Query;
import org.hibernate.Session;

public class Main {

public static void main(String[] args) {
    saveEmployee();

    retrieveEmployee();

}

private static void saveEmployee() {
    Employee employee=new Employee();
    Employee employee1=new Employee();
    Employee employee2=new Employee();
    Employee employee3=new Employee();

    Address address=new Address();
    Address address1=new Address();
    Address address2=new Address();
    Address address3=new Address();

    address.setAddress("1485,Sector 42 b");
    address1.setAddress("1485,Sector 42 c");
    address2.setAddress("1485,Sector 42 d");
    address3.setAddress("1485,Sector 42 a");

    employee.setEmpName("Varun");
    employee1.setEmpName("Krishan");
    employee2.setEmpName("Aasif");
    employee3.setEmpName("Dut");

    address.setEmployee(employee);
    address1.setEmployee(employee1);
    address2.setEmployee(employee2);
    address3.setEmployee(employee3);

    employee.getAddList().add(address);
    employee1.getAddList().add(address1);
    employee2.getAddList().add(address2);
    employee3.getAddList().add(address3);

    Session session=HibernateUtil.getSessionFactory().openSession();

    session.beginTransaction();

    session.save(employee);
    session.save(employee1);
    session.save(employee2);
    session.save(employee3);
    session.getTransaction().commit();
    session.close();
}

private static void retrieveEmployee() {
    try{

    String sqlQuery="select e from Employee e inner join e.addList";

    Session session=HibernateUtil.getSessionFactory().openSession();

    Query query=session.createQuery(sqlQuery);

    List<Employee> list=query.list();

     list.stream().forEach((p)->{System.out.println(p.getEmpName());});     
    session.close();
    }catch(Exception e){
        e.printStackTrace();
    }
}
}

I have used Java 8 for loop for priting the names. Make sure you have jdk 1.8 with tomcat 8. Also add some more records for better understanding.

我已经使用 Java 8 for 循环来打印名称。确保你有 jdk 1.8 和 tomcat 8。另外添加一些更多的记录以便更好地理解。

 public class HibernateUtil {
 private static SessionFactory sessionFactory ;
 static {
    Configuration configuration = new Configuration();

    configuration.addAnnotatedClass(Employee.class);
    configuration.addAnnotatedClass(Address.class);
                  configuration.setProperty("connection.driver_class","com.mysql.jdbc.Driver");
    configuration.setProperty("hibernate.connection.url", "jdbc:mysql://localhost:3306/hibernate");                                
    configuration.setProperty("hibernate.connection.username", "root");     
    configuration.setProperty("hibernate.connection.password", "root");
    configuration.setProperty("dialect", "org.hibernate.dialect.MySQLDialect");
    configuration.setProperty("hibernate.hbm2ddl.auto", "update");
    configuration.setProperty("hibernate.show_sql", "true");
    configuration.setProperty(" hibernate.connection.pool_size", "10");


   // configuration
    StandardServiceRegistryBuilder builder = new StandardServiceRegistryBuilder().applySettings(configuration.getProperties());
    sessionFactory = configuration.buildSessionFactory(builder.build());
 }
public static SessionFactory getSessionFactory() {
    return sessionFactory;
}
} 

回答by Val Blant

You can do it without having to create a real Hibernate mapping. Try this:

您无需创建真正的 Hibernate 映射即可完成此操作。尝试这个：

SELECT * FROM Employee e, Team t WHERE e.Id_team=t.Id_team