枚举构造函数中的 Java 字节类型
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Java byte type in enum constructor
提问by varuog
public enum Rank {
TEN("Ten",1),
NINE("Nine",2),
EIGHT("Eight",0),
SEVEN("Seven",0);
private final String name;
private final int point;
/*
* @param rank should be byte
*/
private Rank(String name,int point)
{
this.name=name;
this.point=point;
}
How to replace int to byte in point. One way i can think of is using TEN("Ten",Byte.parseByte("1"));
如何将 int 替换为字节点。我能想到的一种方法是使用TEN("Ten",Byte.parseByte("1"));
Is there any better or/and shorter approach?
有没有更好或/和更短的方法？
回答by Jashaszun
Just castto a byte, like so:
只是cast到 a byte，像这样：
public enum Rank {
TEN("Ten", (byte)1),
NINE("Nine", (byte)2),
EIGHT("Eight", (byte)0),
SEVEN("Seven", (byte)0);
private final String name;
private final byte point;
private Rank(String name, byte point)
{
this.name = name;
this.point = point;
}
回答by Joni
A shorter approach is casting.
更短的方法是铸造。
TEN("Ten", (byte) 1));
回答by kan
Just a style suggestion, move the cast in the constructor, so it looks cleaner:
只是一个样式建议，在构造函数中移动强制转换，这样看起来更干净：
public enum Rank {
TEN("Ten", 1),
NINE("Nine", 2),
EIGHT("Eight", 0),
SEVEN("Seven", 0);
private final String name;
private final byte point;
private Rank(String name, int point)
{
this.name = name;
this.point = (byte)point;
}
