java 从 Content-Disposition 获取文件名
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Get filename from Content-Disposition
提问by h2c
I'm uploading a blob file from an HTML form to a database using JSP. I need to insert the filename into DB. I know that the filename is stored in the Content-Disposition header, how could I get that?
我正在使用 JSP 将 Blob 文件从 HTML 表单上传到数据库。我需要将文件名插入数据库。我知道文件名存储在Content-Disposition 标头中，我怎么能得到它？
回答by Joop Eggen
If you uploaded the file using JavaEE 6 with HttpServletRequest.getPart:
如果您使用 JavaEE 6 上传文件HttpServletRequest.getPart：
Part part = request.getPart("xxx"); // input type=file name=xxx
String disposition = part.getHeader("Content-Disposition");
String fileName = disposition.replaceFirst("(?i)^.*filename=\"?([^\"]+)\"?.*$", "");
See Part.
见部分。
As @Marc mentioned I did not treat URL encoding. (He also made the quotes around the filename optional.)
正如@Marc 提到的，我没有处理 URL 编码。（他还将文件名周围的引号设为可选。）
fileName = URLDecoder.decode(fileName, StandardCharsets.ISO_8859_1);
Not checked, but HTTP encoding for headers should be the default ISO-8859-1.
未选中，但标头的 HTTP 编码应为默认 ISO-8859-1。
