C++ 无法访问类“士兵”中声明的私有成员
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cannot access private member declared in class 'Soldier'
提问by user2594877
I'm new to OOP and I do not understand how to pass arguments to classes.
我是 OOP 的新手，我不明白如何将参数传递给类。
The class' declaration:
班级声明：
class Soldier
{
Soldier(int SetHealth, int SetStrength);
private:
int health;
int strength;
public:
void attacked();
void healed();
int getHealth();
int getStrength();
};
Definition of the constructor:
构造函数的定义：
Soldier::Soldier(int SetHealth, int SetStrength):
health(SetHealth),
strength(SetStrength)
{
}
When I try passing arguments to the class it says this:
当我尝试将参数传递给类时，它说：
1>------ Build started: Project: ConsoleApplication6, Configuration: Debug Win32 ------
1> ConsoleApplication6.cpp
1>c:\users\user\documents\visual studio 2012\projects\consoleapplication6\consoleapplication6\consoleapplication6.cpp(11): error C2248: 'Soldier::Soldier' : cannot access private member declared in class 'Soldier'
1> c:\users\user\documents\visual studio 2012\projects\consoleapplication6\consoleapplication6\soldier.h(7) : see declaration of 'Soldier::Soldier'
1> c:\users\user\documents\visual studio 2012\projects\consoleapplication6\consoleapplication6\soldier.h(6) : see declaration of 'Soldier'
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========
采纳答案by doctorlove
People have already answered this now, but explicitly:
人们现在已经回答了这个问题，但明确地：
class Soldier
{
private:
int health;
int strength;
public:
Soldier(int SetHealth, int SetStrength);
void attacked();
void healed();
int getHealth();
int getStrength();
};
BTW What are attached and healed going to do? They take no parameters and return nothing. Odd.
顺便说一句，附着和治愈要做什么？它们不接受任何参数，也不返回任何内容。奇怪的。
Edit (in light of recent down vote):
编辑（根据最近的否决票）：
Moving the constructor to the public "section", makes it public. Things start off as privateuntil you say otherwise.
将构造函数移动到公共“部分”，使其public. 事情开始，private直到你另有说法。
回答by undu
Your constructor is private(just as the error message says).
By default, every member of a Classis privateif you don't specify an access level.
您的构造函数是private（就像错误消息所说的那样）。默认情况下，如果您不指定访问级别，则 a 的每个成员Class都是private。
回答by Keval Doshi
The constructor that you have defined has a access level of
您定义的构造函数的访问级别为
private
By default if one does not mention anything, the access level is private So change it to public for access.
默认情况下，如果没有提及任何内容，则访问级别是私有的，因此将其更改为公开以进行访问。
回答by Luchian Grigore
A class's members are implicitly privateunless you change the access level to publicor protected, so Soldier::Soldier(int SetHealth, int SetStrength);is private - ergo you can't access it.
private除非您将访问级别更改为public或protected，否则类的成员是隐式的，因此Soldier::Soldier(int SetHealth, int SetStrength);是私有的 -因此您无法访问它。
回答by Петър Петров
changet constructor declaration to this public Soldier(int SetHealth, int SetStrength);
将构造函数声明更改为此 public Soldier(int SetHealth, int SetStrength);
