Javascript 按字符串对包含数组的数组进行排序
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Sort an array with arrays in it by string
提问by dmnkhhn
I have an array that contains several arrays and I would like to order the arrays based on a certain string within those arrays.
我有一个包含多个数组的数组，我想根据这些数组中的某个字符串对数组进行排序。
var myArray = [
[1, 'alfred', '...'],
[23, 'berta', '...'],
[2, 'zimmermann', '...'],
[4, 'albert', '...'],
];
How can I sort it by the name so that albertcomes first and zimmermanncomes last?
如何按名称对其进行排序，以便阿尔伯特排在第一位，齐默尔曼排在最后？
I know how I would do it if I could use the integer for sorting but the string leaves me clueless.
我知道如果我可以使用整数进行排序，我会怎么做，但字符串让我一无所知。
Thank for your help! :)
感谢您的帮助！:)
回答by Martin Milan
This can be achieved by passing a supporting function as an argument to the Array.sortmethod call.
这可以通过将支持函数作为参数传递给Array.sort方法调用来实现。
Something like this:
像这样的东西：
function Comparator(a, b) {
if (a[1] < b[1]) return -1;
if (a[1] > b[1]) return 1;
return 0;
}
var myArray = [
[1, 'alfred', '...'],
[23, 'berta', '...'],
[2, 'zimmermann', '...'],
[4, 'albert', '...'],
];
myArray = myArray.sort(Comparator);
console.log(myArray);回答by vhallac
You can still use array.sort()with a custom function. Inside the function, simply compare the element that you want to use as your key. For you example, you could use:
您仍然可以使用array.sort()自定义函数。在函数内部，只需比较要用作键的元素即可。例如，您可以使用：
myArray.sort(function(a, b) {
return a[1] > b[1] ? 1 : -1;
});
回答by luschn
There′s an easier way now:
现在有一个更简单的方法：
myArray = myArray.sort(function(a, b) {
return a[1].localeCompare(b[1]);
})
It is case insensitive too.
它也不区分大小写。
Source: https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare
来源：https: //developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare
回答by Brian M. Hunt
In ES6 one might do the relatively pithy:
在 ES6 中，可能会做相对简洁的：
myArray.sort(([a], [b]) => a.localeCompare(b))
or
或者
myArray.sort(([a], [b]) => a < b ? -1 : a > b ? 1 : 0)
The helpful/modern bits being the =>lambda operator, and the [X]argument destructuring.
有用/现代的位是=>lambda 运算符和[X]参数解构。
回答by gordon
Awesome! Compound sort on first element, second element and then third, all ascending in this example, would be
惊人的！对第一个元素、第二个元素和第三个元素进行复合排序，在本例中全部升序，将是
myArray=myArray.sort(function(a,b){
retVal=0;
if(a[0]!=b[0]) retVal=a[0]>b[0]?1:-1;
else if(a[1]!=b[1]) retVal=a[1]>b[1]?1:-1;
else if(a[2]!=b[2]) retVal=a[2]>b[2]?1:-1;
return retVal
});
(multiple sort on more than one column)
（对多于一列进行多重排序）
