ios 获取 UITableView 的选定索引
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Get Selected index of UITableView
提问by iOSDev
I want to have selected index for UITableView.
I have written following code:
我想为UITableView. 我写了以下代码：
NSIndexPath *index = [NSIndexPath indexPathForRow:1 inSection:0];
[tableView scrollToRowAtIndexPath:index
atScrollPosition:UITableViewScrollPositionTop
animated:YES];
This always work for 1st item. I want to have selected index in indexPathForRow.
这始终适用于第一项。我想选择索引indexPathForRow.
Please help. Thanks.
请帮忙。谢谢。
回答by Chris Gummer
NSIndexPath *selectedIndexPath = [tableView indexPathForSelectedRow];
回答by ZevsVU
Get current selected row. May be helpful if you have only one section.
获取当前选定的行。如果您只有一个部分，可能会有所帮助。
- (NSUInteger)currentSellectedRowIndex
{
NSIndexPath *selectedIndexPath = [self.tableView indexPathForSelectedRow];
if (selectedIndexPath) {
return selectedIndexPath.row;
}
else {
return NSNotFound;
}
}
回答by Vineesh TP
Use this code
使用此代码
CGPoint location =[sender locationInView:self.tableView];
NSIndexPath *swipedIndexPath = [self.tableView indexPathForRowAtPoint:location];
UITableViewCell *swipedCell = [self.tableView cellForRowAtIndexPath:swipedIndexPath];
NSIndexPath *indexPath = [self.tableView indexPathForCell:swipedCell];
回答by Kolin Krewinkel
In didSelectRowAtIndexPath, set an interface declared NSIndexPath as the indexpath returned. Then you can scroll to that variable. If you need help, comment and I can give some sample code.
在 didSelectRowAtIndexPath 中，设置一个声明为 NSIndexPath 的接口作为返回的索引路径。然后您可以滚动到该变量。如果您需要帮助，请发表评论，我可以提供一些示例代码。
回答by davidrynn
Swift 4.2
斯威夫特 4.2
let selectedIndexPath = tableView.indexPathForSelectedRow
which is an optional return value.
这是一个可选的返回值。
