在 Bash 中从 File 中读取行并将单词解析为 mailx 参数的变量

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/6756758/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-09-18 00:24:13  来源:igfitidea点击:

Read lines from File in Bash and parse words into variables for mailx parameters

bashsedmailx

提问by Shon

I have a bash script which reads lines from a text file with 4 columns(no headers). The number of lines can be a maximum of 4 lines or less. The words in each line are separated by SPACE character.

我有一个 bash 脚本,它从一个有 4 列(没有标题)的文本文件中读取行。行数最多可以是 4 行或更少。每行中的单词由空格字符分隔。

[email protected]   [email protected];[email protected]   Sub1   MailBody1
[email protected]   [email protected];[email protected]   Sub2   MailBody2
[email protected]   [email protected];[email protected]   Sub3   MailBody3
[email protected]   [email protected];[email protected]   Sub4   MailBody4

Currently, I am parsing the file and after getting each line, I am storing each word in every line into a variable and calling mailx four times. Wondering if is there is an elegant awk/sed solution to the below mentioned logic.

目前,我正在解析文件,在获取每一行后,我将每一行中的每个单词存储到一个变量中并调用 mailx 四次。想知道下面提到的逻辑是否有一个优雅的 awk/sed 解决方案。

  • find total number of lines
  • while read $line, store each line in a variable
  • parse each line as i=( $line1 ), j=( $line2 )etc
  • get values from each line as ${i[0]}, ${i[1]}, ${i[2]}and ${i[3]}etc
  • call mailx -s ${i[2]} -t ${i[1]} -r ${i[0]} < ${i[3]}
  • parse next line and call mailx
  • do this until no more lines or max 4 lines have been reached
  • 找到总行数
  • while read $line,将每一行存储在一个变量中
  • 解析每个行i=( $line1 )j=( $line2 )
  • 从各行获取值 ${i[0]}${i[1]}${i[2]}${i[3]}
  • 称呼 mailx -s ${i[2]} -t ${i[1]} -r ${i[0]} < ${i[3]}
  • 解析下一行并调用 mailx
  • 这样做直到没有更多行或最多 4 行已达到

Do awk or sed provide an elegant solution to the above iterating/looping logic?

awk 或 sed 是否为上述迭代/循环逻辑提供了优雅的解决方案?

回答by John Kugelman

Give this a shot:

试一试:

head -n 4 mail.txt | while read from to subject body; do
    mailx -s "$subject" -t "$to" -r "$from" <<< "$body"
done
  • head -n 4reads up to four lines from your text file.
  • readcan read multiple variables from one line, so we can use named variables for readability.
  • <<<is probably what you want for the redirection, rather than <. Probably.
  • head -n 4从文本文件中最多读取四行。
  • read可以从一行读取多个变量,因此我们可以使用命名变量来提高可读性。
  • <<<可能是您想要的重定向,而不是<. 大概。

回答by moo

The above while loop works well as a simple alternative to sed and awk if you have a lot of control over how to display the lines of text in a file. the read command can use a specified delimiter as well, using the -d flag.

如果您对如何在文件中显示文本行有很多控制权,则上述 while 循环可以很好地作为 sed 和 awk 的简单替代方案。读取命令也可以使用指定的分隔符,使用 -d 标志。

Another simple example:

另一个简单的例子:

I had used mysql to grab a list of users and hosts, putting it into a file /tmp/userlist with text as shown:

我曾使用 mysql 获取用户和主机列表,将其放入带有文本的文件 /tmp/userlist 中,如下所示:

user1 host1
user2 host2
user3 host3

I passed these variables into a mysql command to get grant info for these users and hosts and append to /tmp/grantlist:

我将这些变量传递给 mysql 命令以获取这些用户和主机的授权信息并附加到 /tmp/grantlist:

cat /tmp/userlist | while read user hostname;
do
  echo -e "\n\nGrabbing user $user for host $hostname..."
  mysql -u root -h "localhost" -e "SHOW GRANTS FOR '$user'@$hostname" >> /tmp/grantlist
done