php 每 4 个字符后添加空格
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Add space after every 4th character
提问by user990767
I want to add a space to some output after every 4th character until the end of the string. I tried:
我想在每 4 个字符之后向某些输出添加一个空格，直到字符串结束。我试过：
$str = $rows['value'];
<? echo substr($str, 0, 4) . ' ' . substr($str, 4); ?>
Which just got me the space after the first 4 characters.
这让我在前 4 个字符后得到了空间。
How can I make it show after every 4th ?
我怎样才能让它每 4 次显示一次？
回答by Felix Kling
You can use chunk_split[docs]:
您可以使用chunk_split[文档]：
$str = chunk_split($rows['value'], 4, ' ');
If the length of the string is a multiple of four but you don't want a trailing space, you can pass the result to trim.
如果字符串的长度是 4 的倍数但您不想要尾随空格，则可以将结果传递给trim.
回答by Olemak
Wordwrap does exactly what you want:
Wordwrap 完全符合您的要求：
echo wordwrap('12345678' , 4 , ' ' , true )
will output: 1234 5678
将输出：1234 5678
If you want, say, a hyphen after every second digit instead, swap the "4" for a "2", and the space for a hyphen:
如果你想在每第二个数字后面加一个连字符，把“4”换成“2”，把空格换成一个连字符：
echo wordwrap('1234567890' , 2 , '-' , true )
will output: 12-34-56-78-90
将输出：12-34-56-78-90
回答by Sgarz
Have you already seen this function called wordwrap? http://us2.php.net/manual/en/function.wordwrap.php
你见过这个叫做 wordwrap 的函数吗？ http://us2.php.net/manual/en/function.wordwrap.php
Here is a solution. Works right out of the box like this.
这是一个解决方案。像这样开箱即用。
<?php
$text = "Thiswordissoverylong.";
$newtext = wordwrap($text, 4, "\n", true);
echo "$newtext\n";
?>
回答by Giova
one-liner:
单线：
$yourstring = "1234567890";
echo implode(" ", str_split($yourstring, 4))." ";
This should give you as output:
1234 5678 90
这应该给你作为输出：
1234 5678 90
That's all :D
就是这样：D
回答by Meloman
Here is an example of string with length is not a multiple of 4 (or 5 in my case).
这是一个长度不是 4 的倍数（或在我的情况下为 5）的字符串示例。
function ref_format($str, $step, $reverse = false) {
if ($reverse)
return strrev(chunk_split(strrev($str), $step, ' '));
return chunk_split($str, $step, ' ');
}
Use :
用 ：
echo ref_format("0000000152748541695882", 5);
result: 00000 00152 74854 16958 82
结果：00000 00152 74854 16958 82
Reverse mode use ("BVR code" for swiss billing) :
反向模式使用（“BVR 代码”用于瑞士计费）：
echo ref_format("1400360152748541695882", 5, true);
result: 14 00360 15274 85416 95882
结果：14 00360 15274 85416 95882
Hope it could help some of you.
希望它可以帮助你们中的一些人。
回答by hakre
On way would be to split into 4-character chunks and then join them together again with a space between each part.
方法是分成 4 个字符的块，然后将它们再次连接在一起，每个部分之间有一个空格。
As this would technically miss to insert one at the very end if the last chunk would have exactly 4 characters, we would need to add that one manually (Demo):
由于如果最后一个块正好有 4 个字符，这在技术上会错过在最后插入一个，我们需要手动添加一个（Demo）：
$chunk_length = 4;
$chunks = str_split($str, $chunk_length);
$last = end($chunks);
if (strlen($last) === $chunk_length) {
$chunks[] = '';
}
$str_with_spaces = implode(' ', $chunks);
回答by fdomig
The function wordwrap()basically does the same, however this should work as well.
该功能wordwrap()基本上执行相同的操作，但是这也应该有效。
$newstr = '';
$len = strlen($str);
for($i = 0; $i < $len; $i++) {
$newstr.= $str[$i];
if (($i+1) % 4 == 0) {
$newstr.= ' ';
}
}
回答by Eva
PHP3 Compatible:
PHP3兼容：
Try this:
尝试这个：
$strLen = strlen( $str );
for($i = 0; $i < $strLen; $i += 4){
echo substr($str, $i, 4) . ' ';
}
unset( $strLen );
回答by Nitin Divate
StringBuilder str = new StringBuilder("ABCDEFGHIJKLMNOP");
int idx = str.length() - 4;
while (idx > 0){
str.insert(idx, " ");
idx = idx - 4;
}
return str.toString();
Explanation, this code will add space from right to left:
说明，这段代码会从右到左添加空格：
str = "ABCDEFGH" int idx = total length - 4; //8-4=4
while (4>0){
str.insert(idx, " "); //this will insert space at 4th position
idx = idx - 4; // then decrement 4-4=0 and run loop again
}
The final output will be:
最终输出将是：
ABCD EFGH
