bash 在bash中从模式匹配到文件结尾
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Match from pattern to end of file in bash
提问by Colin
I have been trying to figure out how to use grepin a bash script to match from a pattern to the end of the file. The file is not always the same number of lines each time and is not always [A-Za-z0-9]. I'm trying to migrate from a flat-file based catalog to a database.
我一直在试图弄清楚如何grep在 bash 脚本中使用从模式到文件末尾的匹配。该文件每次的行数并不总是相同，也不总是[A-Za-z0-9]. 我正在尝试从基于平面文件的目录迁移到数据库。
File excerpt:
文件摘录：
First, Last: Doe, John
ID: xxxxxxxx
...
Case Notes:
This "person" does not exist!
Please do not add him.
Thanks.
I need to grab everything from Case Notes:to the end of file. I can't seem to find anything to help out there as there isn't an actual EOF character.
我需要抓取从Case Notes:文件末尾的所有内容。我似乎无法找到任何帮助，因为没有实际的 EOF 字符。
Ideas?
想法？
回答by ajk
An awkscript might be easier:
一个awk脚本可能会更容易：
awk '/^Case Notes:$/ { matched = 1 } matched'
Or if you don't want to see the Case notes:string itself, reverse it:
或者，如果您不想看到Case notes:字符串本身，请将其反转：
awk 'matched; /^Case Notes:$/ { matched = 1 }'
回答by karakfa
idiomatic awksolution would be
惯用的awk解决方案是
awk '/^Case Notes:$/,0'
prints from pattern (inclusive) to end of file.
从模式（包括）打印到文件末尾。
回答by tripleee
sed -n '/^Case notes:/,$p' file >newfile
回答by tripleee
Few years late but you could use
晚了几年，但你可以使用
more +"Case notes:" file
回答by bash-o-logist
Pure bashcan do it
纯bash能做到
declare -i tf=0
while read -r line
do
case "$line" in
*"Case notes"* ) tf=1;
esac
[[ $tf -eq 1 ]] && echo "$line"
done < file
