bash 如何在bash脚本中打印文字字符串“$1”？
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How to print literal string "$1" in bash script?
提问by Ziyaddin Sadigov
I want to print string called "$1". But when I do this with echo it prints string which equals to "$1" variable. How can I print "$1" just like string?
我想打印名为“$1”的字符串。但是当我用 echo 执行此操作时，它会打印等于“$1”变量的字符串。如何像字符串一样打印“$ 1”？
for example:
例如：
set -- "output" # this sets to be "output"
echo # ==> output
But I want this:
但我想要这个：
echo # ==>
回答by fedorqui 'SO stop harming'
You have to escape the $to have it shown:
你必须转义$它才能显示它：
$ echo "$1"
or, as noted by JeremyP in comments, just use single quotes so that the value of $1does not get expanded:
或者，正如 JeremyP 在评论中所指出的，只使用单引号，这样 的值$1就不会被扩展：
$ echo ''
回答by Carlos Campderrós
You need to either:
您需要：
- Enclose the variable in SINGLE quotes:
echo '$1' - Escape the
$sign:echo "\$1"
- 将变量括在单引号中：
echo '$1' - 逃离
$标志：echo "\$1"
