python 如何在python中将列表拆分为给定数量的子列表
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How to split a list into a given number of sub-lists in python
提问by Richard
Possible Duplicates:
splitting a list of arbitrary size into only roughly N-equal parts
How do you split a list into evenly sized chunks in Python?
I need to create a function that will split a list into a list of list, each containing an equal number of items (or as equal as possible).
我需要创建一个函数，将一个列表拆分为一个列表列表，每个列表包含相等数量的项目（或尽可能相等）。
e.g.
例如
def split_lists(mainlist, splitcount):
....
mylist = [1,2,3,4,5,6]
split_list(mylist,2)will return a list of two lists of three elements - [[1,2,3][4,5,6]].
split_list(mylist,2)将返回一个包含三个元素的两个列表的列表 - [[1,2,3][4,5,6]]。
split_list(mylist,3)will return a list of three lists of two elements.
split_list(mylist,3)将返回包含两个元素的三个列表的列表。
split_list(mylist,4)will return a list of two lists of two elements and two lists of one element.
split_list(mylist,4)将返回包含两个元素的两个列表和包含一个元素的两个列表的列表。
I don't care which elements appear in which list, just that the list is divided up as evenly as possible.
我不在乎哪些元素出现在哪个列表中，只关心列表尽可能均匀地划分。
回答by dalloliogm
numpy.split does this already:
numpy.split 已经这样做了：
Examples:
例子：
>>> mylist = np.array([1,2,3,4,5,6])
split_list(mylist,2) will return a list of two lists of three elements - [[1,2,3][4,5,6]].
split_list(mylist,2) 将返回包含三个元素的两个列表的列表 - [[1,2,3][4,5,6]]。
>>> np.split(mylist, 2)
[array([1, 2, 3]), array([4, 5, 6])]
split_list(mylist,3) will return a list of three lists of two elements.
split_list(mylist,3) 将返回包含两个元素的三个列表的列表。
>>> np.split(mylist, 3)
[array([1, 2]), array([3, 4]), array([5, 6])]
split_list(mylist,4) will return a list of two lists of two elements and two lists of one element.
split_list(mylist,4) 将返回两个元素的两个列表和一个元素的两个列表的列表。
You may probably want to add an exception capture for the cases when the remainder of length(mylist)/n is not 0:
您可能希望为 length(mylist)/n 的余数不为 0 的情况添加异常捕获：
>>> np.split(mylist, 4)
ValueErrorTraceback (most recent call last)
----> 1 np.split(mylist, 4)
...
ValueError: array split does not result in an equal division
