Javascript 在javascript中将Date()四舍五入到最接近的5分钟
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Round a Date() to the nearest 5 minutes in javascript
提问by Jick Lee
Using a Date()instance, how might I round a time to the nearest five minutes?
使用Date()实例，我如何将时间四舍五入到最接近的五分钟？
For example: if it's 4:47 p.m. it'll set the time to 4:45 p.m.
例如：如果现在是下午 4:47，它会将时间设置为下午 4:45
回答by Tomasz Nurkiewicz
That's pretty simple if you already have a Dateobject:
如果你已经有一个Date对象，这很简单：
var coeff = 1000 * 60 * 5;
var date = new Date(); //or use any other date
var rounded = new Date(Math.round(date.getTime() / coeff) * coeff)
回答by joshuakcockrell
Round to nearest x minutes
四舍五入到最接近的 x 分钟
Here is a method that will round a date object to the nearest x minutes, or if you don't give it any date it will round the current time.
这是一种将日期对象舍入到最接近的 x 分钟的方法，或者如果您不给它任何日期，它将舍入当前时间。
let getRoundedDate = (minutes, d=new Date()) => {
let ms = 1000 * 60 * minutes; // convert minutes to ms
let roundedDate = new Date(Math.round(d.getTime() / ms) * ms);
return roundedDate
}
// USAGE //
// Round existing date to 5 minutes
getRoundedDate(5, new Date()); // 2018-01-26T00:45:00.000Z
// Get current time rounded to 30 minutes
getRoundedDate(30); // 2018-01-26T00:30:00.000Z
回答by user3767296
I know it is bit late for answer but maybe it can help someone. If you take the minutes by the following
我知道现在回答有点晚了，但也许它可以帮助某人。如果您按以下方式记分
new Date().getMinutes()
you can take the last 5 minutes by
你可以用最后 5 分钟
new Date().getMinutes() - (new Date().getMinutes()%5)
回答by peter.bartos
With ES6 and partial functions it can be elegant:
使用 ES6 和部分函数，它可以很优雅：
const roundDownTo = roundTo => x => Math.floor(x / roundTo) * roundTo;
const roundUpTo = roundTo => x => Math.ceil(x / roundTo) * roundTo;
const roundDownTo5Minutes = roundDownTo(1000*60*5);
const ms = roundDownTo5Minutes(new Date())
console.log(new Date(ms)); // Wed Jun 05 2019 15:55:00 GMT+0200
回答by Shubham Rai
Use this method to get the next 5 minute cycle using pure JS
使用这个方法，使用纯JS获取下一个5分钟的周期
function calculateNextCycle(interval) {
const timeStampCurrentOrOldDate = Date.now();
const timeStampStartOfDay = new Date().setHours(0, 0, 0, 0);
const timeDiff = timeStampCurrentOrOldDate - timeStampStartOfDay;
const mod = Math.ceil(timeDiff / interval);
return new Date(timeStampStartOfDay + (mod * interval));
}
console.log(calculateNextCycle(5 * 60 * 1000)); // pass in milliseconds回答by Malvineous
Probably less efficient but here's another alternative:
可能效率较低，但这是另一种选择：
debug('Current timestamp:', timestamp);
timestamp.setMilliseconds(0);
timestamp.setSeconds(0);
timestamp.setMinutes(Math.round(timestamp.getMinutes() / 5) * 5);
debug('Rounded timestamp:', timestamp);
Current timestamp: 2019-10-22T09:47:17.989Z Rounded timestamp: 2019-10-22T09:45:00.000Z
Current timestamp: 2019-10-22T09:47:17.989Z Rounded timestamp: 2019-10-22T09:45:00.000Z
回答by Vladimir Semashkin
recently found a very efficient way to round off the date to a timeframe
最近发现了一种将日期四舍五入到时间范围的非常有效的方法
in short:
简而言之：
// minutes
var tf = 15; // 5,10,13,15, 60, - what ever you want
var dt = DateTime.UtcNow;
var minues = dt.TimeOfDay.TotalMinutes; // use TotalMinutes, TotalSecibds, TotalMillisecons and etc
var roundedMinutes = (minues - (minues%tf));
var roundedDate = dt.Date.AddMinutes(a);
I bit of my testing in LINQPad
我在 LINQPad 中进行了一些测试
// minutes
var tf = 15; // 5,10,13,15, 60, - what ever you want
var dt = DateTime.UtcNow;
var minues = dt.TimeOfDay.TotalMinutes;
dt.Dump();
minues.Dump();
(ms%tf).Dump();
var a = (minues - (minues%tf));
a.Dump();
dt.Date.AddMinutes(a).Dump();
output:
输出：
13.07.2018 7:43:58 - current date
463,981443103333 - total mins
13,9814431033333 - rest
450 - rounded minutes value
13.07.2018 7:30:00 - rounded date
回答by Danny Hurlburt
There is an NPM package@qc/date-roundthat can be used. Given that you have a Dateinstance to be rounded
有一个可以使用的NPM 包@qc/date-round。鉴于您有一个Date要舍入的实例
import { round } from '@qc/date-round'
const dateIn = ...; // The date to be rounded
const interval = 5 * 60 * 1000; // 5 minutes
const dateOut = round(dateIn, interval)
Then you can use date-fnsto format the date
然后你可以使用date-fns格式化日期
import format from 'date-fns/format';
console.log(format(dateOut, 'HH:mm')) // 24-hr
console.log(format(dateOut, 'hh:mm a')) // 12-hr
