Javascript 如何使用 Express/Node 以编程方式发送 404 响应？
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How to programmatically send a 404 response with Express/Node?
提问by Randomblue
I want to simulate a 404 error on my Express/Node server. How can I do that?
我想在我的 Express/Node 服务器上模拟 404 错误。我怎样才能做到这一点？
回答by Drew Noakes
Nowadays there's a dedicated statusfunctionfor this on the response object. Just chain it in somewhere before you call send.
现在在响应对象上有一个专门的status功能。只需在调用之前将其链接到某个地方即可send。
res.status(404) // HTTP status 404: NotFound
.send('Not found');
回答by Brad
Updated Answer for Express 4.x
Express 4.x 的更新答案
Rather than using res.send(404)as in old versions of Express, the new method is:
res.send(404)新方法不是在旧版本的 Express 中使用，而是：
res.sendStatus(404);
Express will send a very basic 404 response with "Not Found" text:
Express 将发送一个带有“未找到”文本的非常基本的 404 响应：
HTTP/1.1 404 Not Found
X-Powered-By: Express
Vary: Origin
Content-Type: text/plain; charset=utf-8
Content-Length: 9
ETag: W/"9-nR6tc+Z4+i9RpwqTOwvwFw"
Date: Fri, 23 Oct 2015 20:08:19 GMT
Connection: keep-alive
Not Found
回答by rossipedia
You don't have to simulate it. The second argument to res.sendI believe is the status code. Just pass 404 to that argument.
你不必模拟它。res.send我相信的第二个参数是状态代码。只需将 404 传递给该参数即可。
Let me clarify that: Per the documentation on expressjs.orgit seems as though any number passed to res.send()will be interpreted as the status code. So technically you could get away with:
让我澄清一下：根据expressjs.org 上的文档，似乎传递给的任何数字都res.send()将被解释为状态代码。所以从技术上讲，你可以逃脱：
res.send(404);
Edit:My bad, I meant resinstead of req. It should be called on the response
编辑：我的错，我的意思是res而不是req. 应该在响应中调用它
Edit:As of Express 4, the send(status)method has been deprecated. If you're using Express 4 or later, use: res.sendStatus(404)instead. (Thanks @badcc for the tip in the comments)
编辑：从 Express 4 开始，该send(status)方法已被弃用。如果您使用的是 Express 4 或更高版本，请改用：res.sendStatus(404)。（感谢@badcc 在评论中提供提示）
回答by craniumonempty
According to the site I'll post below, it's all how you set up your server. One example they show is this:
根据我将在下面发布的站点，这就是您设置服务器的所有方式。他们展示的一个例子是这样的：
var http = require("http");
var url = require("url");
function start(route, handle) {
function onRequest(request, response) {
var pathname = url.parse(request.url).pathname;
console.log("Request for " + pathname + " received.");
route(handle, pathname, response);
}
http.createServer(onRequest).listen(8888);
console.log("Server has started.");
}
exports.start = start;
and their route function:
以及它们的路由功能：
function route(handle, pathname, response) {
console.log("About to route a request for " + pathname);
if (typeof handle[pathname] === 'function') {
handle[pathname](response);
} else {
console.log("No request handler found for " + pathname);
response.writeHead(404, {"Content-Type": "text/plain"});
response.write("404 Not found");
response.end();
}
}
exports.route = route;
This is one way. http://www.nodebeginner.org/
这是一种方式。 http://www.nodebeginner.org/
From another site, they create a page and then load it. This might be more of what you're looking for.
他们从另一个站点创建一个页面，然后加载它。这可能是您正在寻找的更多内容。
fs.readFile('www/404.html', function(error2, data) {
response.writeHead(404, {'content-type': 'text/html'});
response.end(data);
});
回答by alessioalex
From the Express site, define a NotFound exception and throw it whenever you want to have a 404 page OR redirect to /404 in the below case:
从Express 站点，定义一个 NotFound 异常并在您想要 404 页面时抛出它或在以下情况下重定向到 /404：
function NotFound(msg){
this.name = 'NotFound';
Error.call(this, msg);
Error.captureStackTrace(this, arguments.callee);
}
NotFound.prototype.__proto__ = Error.prototype;
app.get('/404', function(req, res){
throw new NotFound;
});
app.get('/500', function(req, res){
throw new Error('keyboard cat!');
});
回答by Sam
IMO the nicest way is to use the next()function:
IMO 最好的方法是使用该next()函数：
router.get('/', function(req, res, next) {
var err = new Error('Not found');
err.status = 404;
return next(err);
}
Then the error is handled by your error handler and you can style the error nicely using HTML.
然后错误由您的错误处理程序处理，您可以使用 HTML 很好地设置错误样式。
