Java 做 while 循环猜猜游戏
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Do while loop for guessing game
提问by decken
I am writing a simple java guessing game, the game is supposed to randomly pick a number between 1 and 100 and then after you pick the correct number it asks you if you would like to play again. I know i should be able to use a Do while loop to ask if the user would like to play again, but every time I try I cannot make it work. This is my fully functional program without the do while loop. If someone could help me prompt the user if they would like to play again I would be very thankful. I am still very new to programming. Also I apologize if the indenting isn't 100% correct.
我正在编写一个简单的 java 猜谜游戏,该游戏应该随机选择 1 到 100 之间的一个数字,然后在您选择正确的数字后,它会询问您是否想再玩一次。我知道我应该能够使用 Do while 循环来询问用户是否想再次播放,但是每次我尝试都无法使其工作。这是我没有 do while 循环的全功能程序。如果有人能帮我提示用户是否愿意再次玩,我将非常感激。我对编程还是很陌生。如果缩进不是 100% 正确,我也深表歉意。
import java.util.Scanner;
import java.util.Random;
public class GuessingGame
{
public static void main (String [] args)
{
//Variables
Random randomNumber = new Random();
Scanner kbd = new Scanner(System.in);
int computerValue = randomNumber.nextInt(100);
int numberOfTries = 0;
int success = 0;
int guess = 0;
//Logic and While Loop
while (success ==0)
{
System.out.println("please enter an integer betwen 1 and 100 inclusive: ");
guess = kbd.nextInt();
numberOfTries++;
if (guess < 1 || guess > 100){
System.out.println("Invalid input");
}
else if (guess == computerValue){
success++;
System.out.println("Congratulations you won! Your numbers of tries was: " + numberOfTries + " and the number was: " + computerValue);
}
else if (guess < computerValue){
System.out.println("Your guess is too low!");
}
else if (guess > computerValue){
System.out.println("Your guess is too high!");
}
}
}
}
采纳答案by Pol
Try this:
尝试这个:
while(true) {
computerValue = randomNumber.nextInt(100);
numberOfTries = 0;
while (true) {
System.out.println("please enter an integer betwen 1 and 100 inclusive: ");
guess = kbd.nextInt();
numberOfTries++;
if (guess < 1 || guess > 100) System.out.println("Invalid input");
else if (guess == computerValue) {
System.out.println("Congratulations you won! Your numbers of tries was: " + numberOfTries + " and the number was: " + computerValue);
// leave the first loop
break;
}
else if (guess < computerValue) System.out.println("Your guess is too low!");
else if (guess > computerValue) System.out.println("Your guess is too high!");
}
System.out.println("Do you want to play again? (1:Yes/2:No)");
// if input is not yes leave second loop
if(kbd.nextInt() != 1) break;
}
回答by James
Prompt the user if he wants to play again at
提示用户是否想再次玩
else if (guess == computerValue) {
success++;
System.out.println("Congratulations you won! Your numbers of tries was: " + numberOfTries + " and the number was: " + computerValue);
}
If the user inputs yes success--;
如果用户输入 yes success--;
回答by Josh Wein
If you want to use a do while loop this would work.
如果您想使用 do while 循环,这将起作用。
import java.util.Scanner;
import java.util.Random;
public class GuessingGame {
public static void main(String[] args) {
//Variables
Random randomNumber = new Random();
Scanner kbd = new Scanner(System.in);
int computerValue;
int numberOfTries = 0;
int success = 0;
int guess;
boolean playAgain;
//Logic and While Loop
do {
computerValue = randomNumber.nextInt(100);
guess = 0;
playAgain = false;
while (guess != computerValue) {
System.out.println("Please enter an integer betwen 1 and 100 inclusive: ");
guess = kbd.nextInt();
numberOfTries++;
if (guess < 1 || guess > 100) {
System.out.println("Invalid input");
} else if (guess < computerValue) {
System.out.println("Your guess is too low!");
} else if (guess > computerValue) {
System.out.println("Your guess is too high!");
}
}
success++;
System.out.println("Congratulations you won! Your numbers of tries was: " + numberOfTries + " and the number was: " + computerValue);
System.out.println("Would you like to play again?");
switch (kbd.next()) {
case "yes":
playAgain = true;
break;
default:
break;
}
} while (playAgain);
System.out.println("Goodbye");
}
}