bash 文件列表上 awk 的文件大小总和
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Sum of file sizes with awk on a list of files
提问by THX
I have a list of files and want to sum over their file sizes. So, I created a (global) variable as counter and are trying to loop over that list, get the file size with ls and cut&add it with
我有一个文件列表，想总结一下它们的文件大小。因此，我创建了一个（全局）变量作为计数器并尝试遍历该列表，使用 ls 获取文件大小并使用 cut&add
export COUNTER=1
for x in $(cat ./myfiles.lst); do ls -all $x | awk '{COUNTER+=}'; done
However, my counter is empty?
但是，我的柜台是空的？
> echo $COUNTER
> 1
Does someone has an idea for my, what I am missing here?
有人对我有什么想法，我在这里缺少什么？
Cheers and thanks, Thomas
干杯和感谢，托马斯
OK, I found a way piping the result from the awk pipe into a variable (which is probably not elegant but working ;) )
好的，我找到了一种将 awk 管道的结果传送到变量中的方法（这可能不优雅但有效；））
for x in $(cat ./myfiles.lst); do a=$(ls -all $x |awk '{print }'); COUNTER=$(($COUNTER+$a)) ; done
> echo $COUNTER
> 4793061514
回答by Zsolt Botykai
Because you are doing it wrong. Awk is called for every file, so in COUNTERyou got the last file's size.
因为你做错了。awk 为每个文件调用，所以COUNTER你得到了最后一个文件的大小。
A better solution is:
更好的解决方案是：
ls -all <myfiles.lst | awk '{COUNTER+=} END {print COUNTER}'
But you are reinventing the wheel here. You can do something like
但是你在这里重新发明轮子。你可以做类似的事情
du -s <myfiles.lst
(If you have duinstalled. Note: see the comments below my answer about du. I had tested this with cygwinand with that it worked like a charm.)
（如果您已du安装。注意：请参阅我关于 的回答下方的评论du。我已经对此进行了测试，cygwin并且它的效果非常好。）
回答by Richard Lohman
Shorter version of the last:
上一个的简短版本：
ls -l | awk '{sum += } END {print sum}'
Now, say you want to filter by certain types of files, age, etc... Just throw the ls -l into a find, and you can filter using find's extensive filter parameters:
现在，假设您想按某些类型的文件、年龄等进行过滤……只需将 ls -l 放入 find 中，您就可以使用 find 的广泛过滤器参数进行过滤：
find . -type f -exec ls -l {} \; | awk '{sum += } END {print sum}'
回答by neeraj
ls -ltS | awk -F " " {'print '} | awk '{s+=} END {print s}'
