php 将多维数组转化为一维数组
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Turning multidimensional array into one-dimensional array
提问by Tomi Seus
I've been banging my head on this one for a while now.
一段时间以来，我一直在关注这个问题。
I have this multidimensional array:
我有这个多维数组：
Array
(
[0] => Array
(
[0] => foo
[1] => bar
[2] => hello
)
[1] => Array
(
[0] => world
[1] => love
)
[2] => Array
(
[0] => stack
[1] => overflow
[2] => yep
[3] => man
)
And I need to get this:
我需要得到这个：
Array
(
[0] => foo
[1] => bar
[2] => hello
[3] => world
[4] => love
[5] => stack
[6] => overflow
[7] => yep
[8] => man
)
Any ideas?
有任何想法吗？
All other solutions I found solve multidimensional arrays with different keys. My arrays use simple numeric keys only.
我发现的所有其他解决方案都使用不同的键来解决多维数组。我的数组只使用简单的数字键。
回答by deceze
array_reduce($array, 'array_merge', array())
Example:
例子：
$a = array(array(1, 2, 3), array(4, 5, 6));
$result = array_reduce($a, 'array_merge', array());
Result:
结果：
array[1, 2, 3, 4, 5, 6];
回答by hakre
The PHP array_mergeDocsfunction can flatten your array:
PHP array_mergeDocs函数可以展平您的数组：
$flat = call_user_func_array('array_merge', $array);
In case the original array has a higher depth than 2 levels, the SPL in PHP has a RecursiveArrayIteratoryou can use to flatten it:
如果原始数组的深度高于 2 级，PHP 中的 SPL 有一个RecursiveArrayIterator可以用来展平它：
$flat = iterator_to_array(new RecursiveIteratorIterator(new RecursiveArrayIterator($array)), 0);
See as well: How to Flatten a Multidimensional Array?.
另请参阅：如何展平多维数组？.
回答by Grexis
This is really all there is to it:
这就是它的全部内容：
foreach($array as $subArray){
foreach($subArray as $val){
$newArray[] = $val;
}
}
回答by Don't Panic
As of PHP 5.6this can be done more simply with argument unpacking.
从 PHP 5.6 开始，这可以通过参数解包更简单地完成。
$flat = array_merge(...$array);
回答by n00b
foreach ($a as $v1) {
foreach ($v1 as $v2) {
echo "$v2\n";
}
}
where $a is your array name. for details
其中 $a 是您的数组名称。 详情
回答by Hamid Naghipour
As of PHP 5.3 the shortest solution seems to be array_walk_recursive() with the new closures syntax:
从 PHP 5.3 开始，最短的解决方案似乎是使用新的闭包语法的 array_walk_recursive()：
function flatten(array $array) {
$return = array();
array_walk_recursive($array, function($a) use (&$return) { $return[] = $a; });
return $return;
}
回答by rray
In PHP5.6 there other way to solve this problem, combining the functions, array_shift()to remove the first elemente of the original array, array_pus()to add items an new array, the important thing is the of ...splapt/elipse operator it will unpack the return of array_shitf()like an argument.
在 PHP5.6 中还有其他方法可以解决这个问题，结合函数，array_shift()删除原始数组的第一个元素，array_pus()将项目添加到一个新数组中，重要的是...slapt/elipse 运算符它会解包array_shitf()like的返回一个论点。
<?php
$arr = [
['foo', 'bar', 'hello'],
['world', 'love'],
['stack', 'overflow', 'yep', 'man', 'wow']
];
$new = [];
while($item = array_shift($arr)){
array_push($new, ...$item);
}
print_r($new);
Output:
输出：
Array
(
[0] => foo
[1] => bar
[2] => hello
[3] => world
[4] => love
[5] => stack
[6] => overflow
[7] => yep
[8] => man
[9] => wow
)
回答by Kunwar Kishor
I had used this code to resolve same type of problem. so you can also try this.
我曾使用此代码来解决相同类型的问题。所以你也可以试试这个。
function array_flatten($array) {
if (!is_array($array))
{
return FALSE;
}
$result = array();
foreach ($array as $key => $value)
{
if (is_array($value))
{
$result = array_merge($result, array_flatten($value));
}
else {
$result[$key] = $value;
}
}
return $result;
}
回答by Rutunj sheladiya
This will make
这将使
array_walk_recursive($array, function($a) use (&$return) { $return[] = $a; });
回答by Roman
$blocked_dates = array(
'2014' => Array
(
'8' => Array
(
'3' => '1',
'4' => '1',
'6' => '1',
'10' => '1',
'15' => '1',
'25' => '1'
)
),
'2015' => Array
(
'9' => Array
(
'3' => '1',
'4' => '1',
'6' => '1',
'10' => '1',
'15' => '1',
'25' => '1'
)
)
);
RESUTL(ONE DIMENTIONAL ARRAY) :
结果（一维数组）：
$unavailable_dates = array();
foreach ($blocked_dates as $year=>$months) {
foreach ($months as $month => $days) {
foreach ($days as $day => $value) {
array_push($unavailable_dates,"$year-$month-$day");
}
}
}
$unavailable_dates = json_encode($unavailable_dates);
print_r($unavailable_dates);
OUTPUT : ["2014-8-3","2014-8-4","2014-8-6","2014-8-10","2014-8-15","2014-8-25","2015-9-3","2015-9-4","2015-9-6","2015-9-10","2015-9-15","2015-9-25"]
