如何从 URL 中删除 https:// 并在 PHP 的字符串中插入 http:// 而不是它？
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How to remove https:// from URL and insert http:// instead of it in string in PHP?
提问by JohnUS
First, I need to check the URL string, if the protocol of URL is https, then I need to replace httpin PHP.
So the inputs and outputs of this php function must be like this:
首先，我需要检查 URL 字符串，如果 URL 的协议是https，那么我需要http在 PHP 中替换。所以这个php函数的输入输出一定是这样的：
Input -> https://example.com/example/https.php
Output-> http://example.com/example/https.php
Input -> http://example.com/example/https.php
Output-> http://example.com/example/https.php
回答by inhan
This will ensure it's at the beginning of the string and it's followed by ://
这将确保它位于字符串的开头，然后是 ://
$input = 'https://example.com/example/https.php';
echo preg_replace('/^https(?=:\/\/)/i','http',$input);
回答by Captain Insaneo
function remove_ssl ($url) {
if (strpos($url, 'https://') == 0) {
$url = 'http://' . substr($url, 7);
}
return $url;
}
The
这
strpos($url, 'https://') == 0
Is on purpose and is not === because we only want the case when the URL starts with https:// and just replace that one.
是故意的，而不是 ===，因为我们只想要 URL 以 https:// 开头的情况，然后替换那个。
See also: http://php.net/manual/en/function.parse-url.php
另见：http: //php.net/manual/en/function.parse-url.php
...
$parsed_url = parse_url($url);
if ($parsed_url['scheme'] == 'https') {
$url = 'http://' . substr($url, 7);
}
return $url;
...
回答by Vyktor
At first you need to check httpspresence with strpos():
首先，您需要使用以下命令检查https是否存在strpos()：
if( strpos( $url, 'https://') === 0){
(notice ===), than you may extract the all string after https://(that's after first 8 characters, or 5 when keeping original ://) with substr():
（注意===），然后您可以使用以下方法提取所有字符串https://（在前 8 个字符之后，或在保留原始字符时为 5 个字符之后://）substr()：
$url = 'http://' . substr( $url, 8);
回答by Onkar Janwa
$parse = parse_url($url);
if($parse['scheme'] === 'https')
{
$url = str_replace('https','http',$url,1);
}
You can use this solution.
您可以使用此解决方案。
回答by Paul T.
function replace_uri_protocol($uri, $search, $replacement){
$parts = parse_url($uri);
$uri = $replacement."://".$parts["host"].$parts["path"];
if(isset($parts["query"])){
$uri .= "?".$parts["query"];
}
return $uri;
}
回答by Brian Glaz
You can use a combination of str_pos()and str_replace()to accomplish this:
您可以使用的组合str_pos()，并str_replace()做到这一点：
if(str_pos($input,'https:') === 0) {
$output = str_replace('https:','http:',$input,1);
} else {
$output = $input;
}
回答by MAHABUB HOSSAIN RISHAD
Try this it's work on me..
试试这个它对我有用..
$url = 'https://www.example.com';
echo preg_replace("(^https?://)", "http://", $url);
