bash grep 使用另一个命令的输出
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grep using output from another command
提问by bruchowski
Say I have command1which outputs this:
说我有command1哪个输出：
b05808aa-c6ad-4d30-a334-198ff5726f7c
59996d37-9008-4b3b-ab22-340955cb6019
2b41f358-ff6d-418c-a0d3-ac7151c03b78
7ac4995c-ff2c-4717-a2ac-e6870a5670f0
I also have command2which outputs this:
我也有command2输出这个：
b05808aa-c6ad-4d30-a334-198ff5726f7c
59996d37-9008-4b3b-ab22-340955cb6019
Is there a way to grep the output from command1to not include any lines matched from command2, so that the final output would look like this?
有没有办法 grep 输出 fromcommand1不包括任何匹配 from 的行command2，以便最终输出看起来像这样？
2b41f358-ff6d-418c-a0d3-ac7151c03b78
7ac4995c-ff2c-4717-a2ac-e6870a5670f0
回答by Shiplu Mokaddim
Issue this grep
发出这个 grep
command1 | grep -vF -f <(command2)
Here,
这里，
-Fmeans Fixed string match*
-F表示固定字符串匹配*
-vmeans invert match
-v意味着反向匹配
-fmeans the file with patterns
-f表示带有模式的文件
<(command)actually creates a FIFO with that command and use it on redirection.
<(command)实际上使用该命令创建一个 FIFO 并在重定向时使用它。
回答by John1024
To get all the lines from the output of command1that do not appear in the output of command2:
要从 的输出中获取command1未出现在 的输出中的所有行command2：
grep -vFf <(command2) <(command1)
-ftells grepto use patterns that come from a file. In this case, that file is the output of command2. -Ftells grepthat those patterns are to be treated as fixed strings, not regex. -vtells grepto invert its normal behavior and just show lines the lines that do notmatch.
-f告诉grep使用来自文件的模式。在这种情况下，该文件是command2. -F告诉grep这些模式将被视为固定字符串，而不是正则表达式。 -v告诉grep反转其正常行为，只显示不匹配的行。
