php in_array() 期望参数 2 是数组，Classipress 中给出的字符串
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in_array() expects parameter 2 to be array, string given in Classipress
提问by user3597087
I'm using Classipress themefor wordpress, and I'm trying to sticky my featured ads on the on in categories .
我正在使用Classipress themewordpress，并且我正在尝试将我的特色广告粘贴在类别中。
I found a code that is return this error:
我发现了一个返回此错误的代码：
Warning: in_array() expects parameter 2 to be array, string given in loop-ad_listing.php on line 26
To use the sticky on top code, I had to edit two pages and insert two codes and I'll post the error part:
要使用置顶代码，我必须编辑两个页面并插入两个代码，然后我将发布错误部分：
First: loop-ad_listing.php
第一的： loop-ad_listing.php
Code1:
代码1：
global $postisfeatured;
global $featurePostArray;
if ($postisfeatured == "1")
array_push($featurePostArray, $post->ID);
if (in_array($post, "ID", $featurePostArray) && $postisfeatured != "1")
echo '<div class="hide">';
Code2:
代码2：
if ($postisfeatured != "1") {
appthemes_after_endwhile();
$postisfeatured = "";
}
That line: if (in_array($post,"ID",$featurePostArray) && $postisfeatured != "1") {is the error.
那一行：if (in_array($post,"ID",$featurePostArray) && $postisfeatured != "1") {是错误。
回答by andrew
the signature for in_arraylooks like:
的签名in_array看起来像：
in_array($needle, $haystack, $strict = FALSE);
where:
在哪里：
needleis the string,int,resource etc which you're searching for.
needle是您要搜索的字符串、整数、资源等。
haystackis the array in which you're searching
haystack是您要搜索的数组
strict(optional) If (or not) the matched item should be identical (===)
strict（可选）如果（或不）匹配的项目应该是相同的 ( ===)
回答by Intesar Haider
You aren't using the in_arrayfunction as it should be used.
您没有使用in_array应该使用的功能。
In the second parameter you've placed a string (i.e "ID"), it's wrong; you should place the array that you wish to search in, at that spot.
在第二个参数中，您放置了一个字符串（即"ID"），这是错误的；您应该将要搜索的数组放在那个位置。
The outcome should be something like this:
结果应该是这样的：
$valueToSearch = "a";
$arrayToSearch = array("a", "b", "c");
echo in_array($valueToSearch, $arrayToSearch);
回答by sumon cse-sust
You used "ID" as a second parameter which is a string. Try the following:
您使用“ID”作为第二个参数，它是一个字符串。请尝试以下操作：
if ( is_array($featurePostArray) && in_array($post->ID, $featurePostArray) ) {
//some action
}
回答by zoladp
I think I solved this problem. I've got similiar situation in my form field select multiplewhich automatically creates not simple variable but array type variable(PHP weak var types). So when I declared the value at first in my code:
我想我解决了这个问题。我的表单字段中有类似的情况，select multiple它自动创建的不是简单变量而是数组类型变量（PHP 弱变量类型）。因此，当我首先在代码中声明该值时：
$lang='';- then
$lang=$_POST['lang']; <select id="lang" name="lang[]" multiple size="3"> <option value="en"<?php if(in_array('en',$lang)) echo ' selected';?>>English</option> <option value="fr"<?php if(in_array('fr',$lang)) echo ' selected';?>>French</option> <option value="pl"<?php if(in_array('pl',$lang)) echo ' selected';?>>Polish</option> </select><br>- and then I tried to run script and select none of the option I got known error "in_array() expects parameter 2..."
- solution isto set(in point 1.) to empty array
$lang=array();
$lang='';- 然后
$lang=$_POST['lang']; <select id="lang" name="lang[]" multiple size="3"> <option value="en"<?php if(in_array('en',$lang)) echo ' selected';?>>English</option> <option value="fr"<?php if(in_array('fr',$lang)) echo ' selected';?>>French</option> <option value="pl"<?php if(in_array('pl',$lang)) echo ' selected';?>>Polish</option> </select><br>- 然后我尝试运行脚本并没有选择任何选项我得到了已知错误“in_array() 期望参数 2...”
- 解决方案是将（在第 1 点中）设置为空数组
$lang=array();
