bash Linux 源代码在 .sh 文件中不起作用？
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Linux source does not work in .sh file?
提问by Marc
I have a .sh (start_sim.sh) and a .bash (sim_sources.bash) file.
The sim_sources.bashfile is called from within the start_sim.shand should set an environment variable $ROBOTto a certain value. However the ROBOTvariable never changes when I call ./start_sim.sh. Is there a fundamental mistake in the way I am trying to do this?
我有一个 .sh ( start_sim.sh) 和一个 .bash ( sim_sources.bash) 文件。该sim_sources.bash文件是从内部调用的，start_sim.sh并且应该将环境变量$ROBOT设置为某个值。但是，ROBOT当我调用./start_sim.sh. 我尝试这样做的方式是否存在根本性错误？
start_sim.shcontains:
start_sim.sh包含：
#!/bin/bash
echo -n "sourcing sim_sources.bash..."
source /home/.../sim_sources.bash
echo "done."
sim_sources.bashcontains:
sim_sources.bash包含：
# set the robot id
export ROBOT=robot
EDIT: Could you also propose a way to work around this issue? I would still need to set variables from with in the .bash file.
编辑：您能否还提出一种解决此问题的方法？我仍然需要在 .bash 文件中设置变量。
EDIT2: Thanks for your replys! Finally I ended up solving it with a screen and stuffing commands to it:
EDIT2：感谢您的回复！最后我最终用一个屏幕和填充命令来解决它：
echo -n "starting screen..."
screen -dmS "sim_screen"
sleep 2
screen -S "sim_screen" -p 0 -X stuff "source /home/.../sim_sources.bash$(printf \r)"
sleep 5
screen -S "sim_screen" -p 0 -X stuff "source /home/.../start_sim.sh$(printf \r)"
回答by Brian Agnew
You're setting the ROBOTvariable inthe start_sim.sh script, but that's notavailable to parent processes (your spawning shell/command-prompt).
你设置的ROBOT变量中的start_sim.sh script，但是这并不适用于父进程（您的产卵壳/命令提示符）。
Exporting a variable e.g. export ROBOT=robotmakes the variable available to the current process and child processes. When you invoke ./start_sim.shyou're invoking a new process.
导出一个变量，例如export ROBOT=robot使该变量可用于当前进程和子进程。当您调用时，./start_sim.sh您正在调用一个新流程。
If you simply source start_sim.shin your shell, that script runs as part of your shell process and then your variable will be available.
如果您只是source start_sim.sh在 shell 中，该脚本将作为 shell 进程的一部分运行，然后您的变量将可用。
回答by vegi
As Brian pointed out the variables are not available outside of the script.
正如布赖恩指出的那样，变量在脚本之外不可用。
Here a adapted script that shows this point:
这是一个显示这一点的改编脚本：
#!/bin/bash
echo -n "sourcing sim_sources.bash..."
. sim_sources.bash
echo $ROBOT
echo "done."
The workaround you are asking for is to start a new shell from the actual shell with the environmental values already set:
您要求的解决方法是从已设置环境值的实际 shell 启动一个新 shell：
#!/bin/bash
echo -n "sourcing sim_sources.bash..."
. sim_sources.bash
echo "done."
bash
This results in:
这导致：
bash-4.1$ printenv | grep ROBOT
ROBOT=robot
回答by sudhanshu
I am on Ubuntu 16.04
我在 Ubuntu 16.04
I used /bin/sh instead of /bin/bash and it works !
我使用 /bin/sh 而不是 /bin/bash 并且它有效！
