javascript 获取之前在 Angularjs ui-router 中的位置
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Get previous location in Angularjs ui-router
提问by HP.
I know we can use fromStateand fromParamsin the $stateChangeSuccessto get all information about previous location. Like said here:
我知道我们可以使用fromState和fromParamsin$stateChangeSuccess来获取有关先前位置的所有信息。就像这里说的：
Angular - ui-router get previous state
$rootScope.$on('$stateChangeSuccess', function (ev, to, toParams, from, fromParams) {
});
But is there niceway to parse it into the url / locationthough? For example:
但是有没有很好的方法可以将它解析为url / location呢？例如：
State: /page/:id/paragraph/:line
Params: id and line, etc..
状态：/page/:id/paragraph/:line
参数：id 和 line 等。
What I want:
我想要的是：
/page/3/paragraph/5 ...
/page/3/paragraph/5 ...
I mean this could get messy with bunch of params. Plus Angularjs ui-routercould also have {{ id }}as params too instead of :id. Isn't there a function to do this already or I have to use RegEx? And if so, what is the RegEx string to use?
我的意思是这可能会因一堆参数而变得混乱。PlusAngularjs ui-router也可以使用{{ id }}as 参数而不是:id. 是不是已经有一个函数可以做到这一点，或者我必须使用 RegEx？如果是这样，要使用的 RegEx 字符串是什么？
Thanks.
谢谢。
回答by Ilan Frumer
Use $state.hrefto get the url:
使用$state.href得到的网址：
$rootScope.$on('$stateChangeSuccess', function (ev, to, toParams, from, fromParams) {
// $state.href(from, fromParams)
});
You can also pass optionsas a third paramerer.
Read the Docsfor more information.
您还可以将选项作为第三个参数传递。
阅读文档了解更多信息。
回答by gonzofish
Not much differently, but you could do:
没什么不同，但你可以这样做：
$rootScope.$on('$routeChangeStart', function (event, next, current) {
});
And just store the current. The function there is a lot less to deal with than $routeChangesuccess.
并且只存储电流。需要处理的函数比$routeChangesuccess.
回答by Michael Tot Korsgaard
using window.history.back()will return you to the previous url.
usingwindow.history.back()将使您返回到上一个 url。
