如何从 Java 验证 WSDL URL 是否已启动并正在运行？
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How to validate WSDL URL is up and running or not from Java?
提问by Sriks
I wanted to check WSDL url is valid or not from Java code. So that I can use another url based on that.
我想从 Java 代码中检查 WSDL url 是否有效。这样我就可以在此基础上使用另一个 url。
So I am checking the code like this.
所以我正在检查这样的代码。
private boolean isValidWsdlURL(String wsdlUrl)
{
UrlValidator urlValidator = new UrlValidator();
if(urlValidator.isValid(wsdlUrl))
{
return true;
}
logger.info("WSDL URL is not valid...");
return false;
}
But its alwys returning false though I have valid URL. WSDL URL Ex:http://www.sample.com/MyWsdlService?wsdl
但是尽管我有有效的 URL，它总是返回 false。 WSDL URL 例如：http : //www.sample.com/MyWsdlService?wsdl
Because URL ends with ?wsdl How to check the code? Looks we need only "http://www.sample.com" for UrlValidator to pass.
因为 URL 以 ?wsdl 结尾怎么查代码？看起来我们只需要“ http://www.sample.com”就可以通过 UrlValidator。
回答by Yair Zaslavsky
You're trying to validate a WSDL URL? Why not use the java.net.URL class ?
And do something like:
您正在尝试验证 WSDL URL？为什么不使用 java.net.URL 类？
并执行以下操作：
String urlStr = "http://www.example.com/helloService?wsdl";
URL url = null;
try {
url = new URL(urlStr);
URLConnection urlConnection = url.openConnection()
} catch (MalformedURLException ex) {
System.out.println("bad URL");
} catch (IOException ex) {
System.out.println("Failed opening connection. Perhaps WS is not up?");
}
When I inserted bad URLs like htt2p instead of http I got - "bad url" print
当我插入像 htt2p 而不是 http 这样的错误 URL 时，我得到了“错误 url”打印
回答by Sriks
Try this.. Its working for me now. Thanks @zaske
试试这个..它现在对我有用。谢谢@zaske
public class TestWSDL {
public static void main(String args[]) {
String urlStr = "http://www.example.com:8080/helloService?wsdl";
URL url = null;
URLConnection urlConnection = null;
try {
url = new URL(urlStr);
urlConnection = url.openConnection();
if(urlConnection.getContent() != null) {
System.out.println("GOOD URL");
} else {
System.out.println("BAD URL");
}
} catch (MalformedURLException ex) {
System.out.println("bad URL");
} catch (IOException ex) {
System.out.println("Failed opening connection. Perhaps WS is not up?");
}
}
}
回答by Issam Ressani
import org.apache.commons.validator.UrlValidator;
public class ValidateUrlExample{
公共类 ValidateUrlExample{
public static void main(String[] args) {
UrlValidator urlValidator = new UrlValidator();
//valid URL
if (urlValidator.isValid("http://www.mkyong.com")) {
System.out.println("url is valid");
} else {
System.out.println("url is invalid");
}
//invalid URL
if (urlValidator.isValid("http://invalidURL^$&%$&^")) {
System.out.println("url is valid");
} else {
System.out.println("url is invalid");
}}
}
for more informations: https://www.mkyong.com/java/how-to-validate-url-in-java/
更多信息：https: //www.mkyong.com/java/how-to-validate-url-in-java/
