java java错误未报告的异常java.lang.Exception; 必须被捕获或声明被抛出
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java error unreported exception java.lang.Exception; must be caught or declared to be thrown
提问by monika
import java.io.FileInputStream;
import org.apache.commons.codec.binary.Base64;
public class Encode
{
//file path ex : C:\Program Files\Cordys\Web\reports\I0001180.pdf
public static String encodeFileStream(String filePath) throws Exception
{
StringBuffer sb=new StringBuffer();
try
{
FileInputStream fin = new FileInputStream(filePath);
//StringBuffer sb=new StringBuffer();
int lineLength = 72;
byte[] buf = new byte[lineLength/4*3];
while (true)
{
int len = fin.read(buf);
if (len <= 0)
{
break;
}
//new Base64().encode(byte);
//sb.append(Base64.encode(buf));
//sb.append(Base64.encodeBase64(buf));
Base64 b = new Base64();
sb.append(b.encode(buf));
//return sb.toString();
}
}
catch(Exception e)
{
return e.getMessage();
}
return sb.toString();
}
public static void main(String args[])
{
String s="";
s=encodeFileStream("E:/CSSDocument/Test.pdf");
}
}
回答by Bringer128
Your method "encodeFileStream" throws Exception. You are catching it in that method so you don't need to declare it in your method declaration.
您的方法“encodeFileStream”抛出异常。您正在该方法中捕获它，因此您无需在方法声明中声明它。
Either:
任何一个：
- Remove "throws Exception" from the declaration of encodeFileStream, or
- Add "throws Exception" to the declaration of main(String[] args)
- 从 encodeFileStream 的声明中删除“抛出异常”，或
- 在 main(String[] args) 的声明中添加“throws Exception”
回答by Christian Kuetbach
You don't catch the Exception, which may be thrown by encodeFileStream():
你没有捕捉到异常，它可能被抛出encodeFileStream()：
public static void main(String args[]) throws Exception{
String s="";
s=encodeFileStream("E:/CSSDocument/Test.pdf");
}
would help, but this is not what I would call "Good exception handling".
会有所帮助，但这不是我所说的“良好的异常处理”。
